Answer:
1.4
Step-by-step explanation:
Answer:
Area shaded part = 116 to three sig digs.
Step-by-step explanation:
I don't know if your answer is correct or not, but the number of sig digs is not. The way the question has been posed is not to 3 sig digs either.
The answer should be 116 if they want it to three sig digs.
Let's see if the answer is correct
Area of the whole circle.
- Area of a circle = pi*r^2
- r = 6.5 cm Note: this is 2 sig digs.
- pi= 3.14
- Area = 3.14 * 6.5^2
- Area = 3.14 * 42.25
- Area= 132.665
Area of unshaded smaller circle
- pi = 3.14
- r = 2.3
- Area = 3.14 * 2.3^2
- Area = 3.14 * 5.29
- Area = 16.61
Area of the shaded part
- Area of shaded part = area of the whole circle - Area of smaller circle
- Area of the shaded part = 132.66 - 16.61
- Area of the shaded part = 116.01
- To 3 sig digs is 116
Answer:
a. 13%
b. 20%
c. 2%
Step-by-step explanation:
The best way to solve this problem is by drawing a Venn diagram. Draw a rectangle representing all the fourth-graders. Draw two overlapping circles inside the rectangle. Let one circle represent proficiency in reading. This circle is 85% of the total area (including the overlap). And let the other circle represent proficiency in math. This circle is 78% of the total area (including the overlap). The overlap is 65% of the total area.
a. Since the overlap is 65%, and 78% are proficient in math, then the percent of all students who are proficient in math but not reading is the difference:
78% − 65% = 13%
b. Since the overlap is 65%, and 85% are proficient in reading, then the percent of all students who are proficient in reading but not math is the difference:
85% − 65% = 20%
c. The percent of students not proficient in reading or math is 100% minus the percent proficient in only reading minus the percent proficient in only math minus the percent proficient in both.
100% − 20% − 13% − 65% = 2%
See attached illustration (not to scale).