Answer:
3 strain would still alive after 48 hours
Step-by-step explanation:
Initial population of virus = 40000 grams
A certain virus is dying off at a rate of 18% per hour.
We are supposed to find how much of the strain would still be alive after 48 hours
Formula : ![N(t)=N_0(1-r)^t](https://tex.z-dn.net/?f=N%28t%29%3DN_0%281-r%29%5Et)
=Initial population
N(t)= Population after t hours
r = rate of decrease = 18% = 0.18
t = time = 48 hours
So,the strain would still be alive after 48 hours=![40000(1-0.18)^{48}=2.91 \sim 3](https://tex.z-dn.net/?f=40000%281-0.18%29%5E%7B48%7D%3D2.91%20%5Csim%203)
Hence 3 strain would still alive after 48 hours
Answer:
Step-by-step explanation:
log8 62 = x1
8^x1= 62
8^2 =64 >62 so <u>x1<2</u>
log7 50=x2
7^x2=50
7^2=49<50 so <u>x2>2</u>
we have, x1<2 and 2<x2
x1<2<x2
x1<x2
log8 62<log7 50