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3 years ago

The radius of a circle measures 8 in.

1 answer:

6 0

Answer: 50.24

To find the circumference of a circle you multiply the diameter of a circle by pi, 3.14, the diameter is 2 x the radius which would be 8x2 which is 16. Then multiply 16x3.14 giving you 50.24

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Please help my geometry assginment, brainly if answer properly

QveST [7]

Answer:

Please mark me brainliest :) Hope it helps

Step-by-step explanation:

So basically, since CD and AB are parallel, that means that angle2 and angle3 are similar, due to the corresponding angle postulate. Furthermore, it is given that AG and CE are similar, so angle1 and angle2 are similar on the same principle.

This means that angle3 and angle4 are similar, since it is given that angle1 and angle4 are similar. A bisecting line divides a whole angle into two, equal value angles, and since ECF is composed of angle3 and angle4, and angle3 and angle4 are the same value, that means the line that forms angle3 and angle4 is bisecting the ECF, therefore CD bisects ECF.

5 0

3 years ago

Consider the system of quadratic equations \begin{align*} y &=3x^2 - 5x, \\ y &= 2x^2 - x - c, \end{align*}where $c$ is

shtirl [24]

Hello, we need to solve this system, c being a real number.

$\begin{cases}y &= 3x^2-5x\\y &= 2x^2-x-c\end{cases}$

y=y, right? So, it comes.

$3x^2-5x=2x^2-x-c\\\\3x^2-2x^2-5x+x+c=0\\\\\boxed{x^2-4x+c=0}$

We can compute the discriminant.

$\Delta=b^2-4ac=4^2-4c=4(4-c)$

If the discriminant is 0, there is 1 solution.

It means for $4(4-c)=0 4-c=0 \boxed{c=4}$

And the solution is

$x_2=x_1=\dfrac{4}{2}=2$

If the discriminant is > 0, there are 2 real solutions.

It means 4(4-c) > 0 <=> 4-c > 0 <=> $\boxed{c$

And the solution are

$x_1=\dfrac{4-\sqrt{4(4-c)}}{2}=\dfrac{4-2\sqrt{4-c}}{2}=2-\sqrt{4-c}\\\\x_2=2+\sqrt{4-c}$

If the discriminant is < 0, there are no real solutions.

It means 4(4-c) < 0 <=> 4-c < 0 <=> $\boxed{c>4}$

There are no real solutions and the complex solutions are

$x_1=\dfrac{4-\sqrt{4(4-c)}}{2}=\dfrac{4-2\sqrt{i^2(c-4)}}{2}=2-\sqrt{c-4}\cdot i\\\\x_2=2+\sqrt{c-4}\cdot i$

Thank you.

8 0

4 years ago

Can you prove that the quadrilateral is a parallelogram based on the information? Support your response with an explanation. (4

kompoz [17]

A: yes, because the opposite sides are congruent and parallel, it is a parallelogram.

b: yes, because the diagonals bisect each other, it is a parallelogram.

7 0

4 years ago

A rectangle was rearranged to form a parallelogram. How is the height of the parallelogram similar to and different from the wid

Daniel [21]

A parallelogram is just a rectangle with the sides angled, it’s pretty much the same as a rectangle and all your working out should be the same as a rectangle

5 0

3 years ago

Determine m<br><br> Please help me with this question

Flura [38]

Answer:

m<DCA = 40

Step-by-step explanation:

m<DAC = 90

m<CDA = 50

m<DCA = 180 - 90 - 50 = 40

4 0

4 years ago