Probability that no zebras collide is 0.25
The zebras are represented as z1, z2 and z3.
Z1 to B, Z2 to C, and Z3 to A come first 
Following that, z1 to C, z2 to A, and z3 to B = 
Consequently, the likelihood of no collision is 2×1/8 = 0.25.
<h3>
What are the types of probability distributions ?</h3>
Discrete and continuous probability distributions are the two main categories in which probability distributions fall. There are numerous varieties of probability distributions within each category.
- The number of favorable outcomes of an event divided by the total number of possible outcomes of an event can be used to calculate the probability of an event.
- The likelihood of a sure or certain event is one.
- The likelihood of an impossibility is 0 (0).
- Every event has a probability between 0 and 1.
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<span>The function can be described as
b(p)= player receives 10 bonus points
</span>b(p)= p+10<span>
s(p)= increases 5% of the player’s current points
</span>s(p)= <span>p*(100%+5%)= p*1.05
then </span><span> (s ∘ b)(p) would be
</span><span>s(p)= p*1.05
(s ∘ b)(p)= (p+10)*1.05
</span>(s ∘ b)(p)= 1.05p+10.5
Least. 0.41, 0.5, 3/5 Greatest
Answer:
No solutions
Step-by-step explanation:
6x+2y=20
-3x-y=-4 (by rewriting)
So
6/-3 = 2/-1≠20/-4
-2=-2≠-5
So it has no solutions