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Alexeev081 [22]
2 years ago
6

What objects in your everyday lives are in the shape of a triangular prism?

Mathematics
2 answers:
Svetach [21]2 years ago
4 0

Answer:

wedge of cheese, slice of watermelon, slice of cake, roof of a house, door-stopper

Step-by-step explanation:

bearhunter [10]2 years ago
4 0

Answer:

wedge of cheese, slice of watermelon, slice of cake, roof of a house, door-stopper

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The graph below represents the solution set of which inequality?
natulia [17]

Answer:

option: B (x^2+2x-8) is correct.

Step-by-step explanation:

We are given the solution set as seen from the graph as:

(-4,2)

1)

On solving the first inequality we have:

x^2-2x-8

On using the method of splitting the middle term we have:

x^2-4x+2x-8

⇒  x(x-4)+2(x-4)=0

⇒ (x+2)(x-4)

And we know that the product of two quantities are negative if either one of them is negative so we have two cases:

case 1:

x+2>0 and x-4

i.e. x>-2 and x<4

so we have the region as:

(-2,4)

Case 2:

x+2 and x-4>0

i.e. x<-2 and x>4

Hence, we did not get a common region.

Hence from both the cases we did not get the required region.

Hence, option 1 is incorrect.

2)

We are given the second inequality as:

x^2+2x-8

On using the method of splitting the middle term we have:

x^2+4x-2x-8

⇒ x(x+4)-2(x+4)

⇒ (x-2)(x+4)

And we know that the product of two quantities are negative if either one of them is negative so we have two cases:

case 1:

x-2>0 and x+4

i.e. x>2 and x<-4

Hence, we do not get a common region.

Case 2:

x-2 and x+4>0

i.e. x<2 and x>-4

Hence the common region is (-4,2) which is same as the given option.

Hence, option B is correct.

3)

x^2-2x-8>0

On using the method of splitting the middle term we have:

x^2-4x+2x-8>0

⇒ x(x-4)+2(x-4)>0

⇒ (x-4)(x+2)>0

And we know that the product of two quantities are positive if either both of them are negative or both of them are positive so we have two cases:

Case 1:

x+2>0 and x-4>0

i.e. x>-2 and x>4

Hence, the common region is (4,∞)

Case 2:

x+2 and x-4

i.e. x<-2 and x<4

Hence, the common region is: (-∞,-2)

Hence, from both the cases we did not get the desired answer.

Hence, option C is incorrect.

4)

x^2+2x-8>0

On using the method of splitting the middle term we have:

x^2+4x-2x-8>0

⇒ x(x+4)-2(x+4)>0

⇒ (x-2)(X+4)>0

And we know that the product of two quantities are positive if either both of them are negative or both of them are positive so we have two cases:

Case 1:

x-2 and x+4

i.e. x<2 and x<-4

Hence, the common region is: (-∞,-4)

Case 2:

x-2>0 and x+4>0

i.e. x>2 and x>-4.

Hence, the common region is: (2,∞)

Hence from both the case we do not have the desired region.

Hence, option D is incorrect.




5 0
3 years ago
Evaluate each expression for the given value (please answer all)
Anna [14]

Answer:

-20a - 65 = -104  for  a = 2.7

-6x + 52 = 45  for  x = 1 1/6

Step-by-step explanation:

-20a - 50  for  a = 2.7

Insert 2.7 in for a.

-20(2.7) - 50 = -54 - 50 = -104

-6x + 52  for  x = 1 1/6

Insert 1 1/6 for x.

-6(1 1/6) + 52 = -7 + 52 = 45

8 0
3 years ago
Evaluate 2xsquared by 2 − 5y over 3x −y when x = 2 and y = -4.
Arisa [49]
(2x^2 -5y)/(3x-y)
((2*2)^2-(5*-4))/((3*-4)-(-4))
(4^2+20)/(-12+4)
36/-8
-4.5
8 0
2 years ago
Solve for y.<br> y + 1.05 = 7.26<br> y = -6.21<br> y = -8.31<br> y = 6.21<br> y = 8.31
Naddik [55]
Y=6.21
hdjsakkaksk
hejsksksjsk
3 0
2 years ago
QUICK HELP ILL GIVE BRAINLIEST
Zigmanuir [339]

Answer:

When I first saw you... and you act like a baka..

Step-by-step explanation:

6 0
2 years ago
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