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3 years ago

A card is drawn from a well-shuffled deck of 52. Find p(drawing a face or a 4)

Mathematics

1 answer:

Musya8 [376]3 years ago

4 0

Answer:

the answer is none of those it is 4/13

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What is the vertex and axis of symmetry for y=4x^2-12x+9?

VLD [36.1K]

Answer:

axis of symmetry x=3/2

vertex (3/2, 0)

Step-by-step explanation:

to find the axis of symmetry we use h = -b/2a

where ax^2 + bx+c

h = -(-12)/2(4)

h= 12/8

h = 3/2

the axis of symmetry is x = 3/2

the x coordinate of the vertex is h x=3/2

to find k, the y coordinate of the vertex, substitute x=3/2 into the equation

y=4x^2-12x+9

y=4(3/2) ^2-12(3/2)+9

= 4 (9/4) - 6*3 +9

= 9-18+9

= 0

the vertex (3/2, 0)

4 0

3 years ago

In Europe, 53% of the flowers of the Rewardless Orchid, Dactylorhiza sambucina, are yellow, whereas the remaining flowers are pu

stich3 [128]

Answer:

a. The probability of taking out a purple flower is 0.47.

b. The probability that out of a sample of 5 flowers at least 3 flowers are yellow 0.56.

c. The standard deviation of the distribution for proportion of yellow flowers is 0.22.

d. The probability that out of the 263 samples, at most 150 of them are yellow is 0.90.

Step-by-step explanation:

7 0

3 years ago

A recipe calls for 5/8 cups butter. Angie wants to triple the recipe but she has only 1 1/4 cups of butter

Alisiya [41]

The recipe calls for 5/8 cups butter and Angie wants to triple the recipe.

Therefore, if Angie is tripling the recipe, she is multiplying all of the ingredients in the recipe by 3.

So for the butter, this would be:

5/8 * 3 = 15/8

Next, we should turn this improper fraction into a mixed number so that we can compare it to the amount of butter that Angie has.

15/8 = 1 7/8

1 7/8 > 1 1/4

Thus, Angie DOES NOT have enough butter to triple the recipe.

8 0

2 years ago

Help! will appreciate

Lera25 [3.4K]

Sorry I've got on idea

4 0

3 years ago

Consider an experiment with sample space S 5 50, 1, 2, 3, 4, 5, 6, 7, 8, 96 and the events A 5 {0, 2, 4, 6, 8} B 5 {1, 3, 5, 7,

Brut [27]

Answer with Step-by-step explanation:

S={0,1,2,3,4,5,6,7,8,9}

A={0,2,4,6,8}

B={1,3,5,7,9}

C={0,1,2,3,4}

D={5,6,7,8,9}

a.A'=S-A

A'={0,1,2,3,4,5,6,7,8,9}-{0,2,4,6,8}

A'={1,3,5,7,9}

b.C'=S-C

C'={0,1,2,3,4,5,6,7,8,9}-{0,1,2,3,4}

C'={5,6,7,8,9}

c.D'=S-D

D'={0,1,2,3,4,5,6,7,8,9}-{5,6,7,8,9}

D'={0,1,2,3,4}

d. $A\cup B=$ {0,2,4,6,8} $\cup$ {1,3,5,7,9}

$A\cup B=$ {0,1,2,3,4,5,6,7,8,9}=S

e. $A\cup C$ ={0,2,4,6,8} $\cup$ {0,1,2,3,4}

$A\cup C$ ={0,1,2,3,4,6,8}

f. $A\cup D$ ={0,2,4,6,8} $\cup$ {5,6,7,8,9}

$A\cup D$ ={0,2,4,5,6,7,8,9}

8 0

3 years ago