Try this option:
1. if 8*x²+b*x+3=8*x²+p*x+q*x+3, then ⇒ b=p+q.
2. p*q = max_value (b²/2), if p=q=0.5*b, and p*q→-oo, if p>0 and q<0 or p>0 q<0.
3. example:
given 8x²+10x+3, the student rewrites it as a) 8x²+5x+5x+3 (5*5=25-max value); b) 8x²+0.01x+9.99x+3 (9.99*0.01=0.0999→0); c) 8x²-20x+30x+3 (p*q=-600).
answer: (-oo;0.5b²)
Y=14/15x-37/15
Step-by-step explanation:
Answer:
i would say the 3rd one
Step-by-step explanation:
Given three points, it is possible to draw a circle that passes through all three. The perpendicular bisectors of a chords always passes through the center of the circle. By this method we find the center and can then draw the circle. This is virtually the same as constructing the circumcircle a triangle.
Answer:
18.36
Step-by-step explanation:
