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1 year ago

Nancy wants to buy a sweater that is priced at $75. If the store is running a 60% off sale, what will be the

Mathematics

1 answer:

AleksAgata [21]1 year ago

3 0

Answer:

$30.00

Step-by-step explanation:

The original price of the sweater is $75.00. The new sale price is the original price of 100% less 60% of the original price. That means the sales price is 40% of the original price.

You can do this 2 ways:

1. $75 x 60% or .60 = $45

$75-45 = $30

2. $75 x 40% or .40 = $30

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When a number is increased by 8.2%, the result is 106. What is the original number to the nearest tenth?

ruslelena [56]

Answer:

Step-by-step explanation:

Let the original number = x

$x+\frac{8.2}{100}*x=106\\\\x+0.082x=106\\\\1.082x=106\\\\x=\frac{106}{1.082}\\\\x=\frac{106*1000}{1.082*1000}\\\\x=\frac{106000}{1082}\\\\x=97.96\\\\$

x=98.0

x=98

4 0

2 years ago

Based on the table, what is Nick's rate?

Cerrena [4.2K]

Nicks rate is 7 yards per second.

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3 years ago

Use the sign ratio to deride a relationship between angle inside measures in a triangle

kirill [66]

Answer:

Derided means to mock/scorn/express contempt for.

Step-by-step explanation:

it means that the monster is kind of blinded by his excessive pride of himself.

4 0

2 years ago

How many different integers between $100$ and $500$ are multiples of either $6,$ $8,$ or both?

nirvana33 [79]

We need to find the number of integers between 100 and 500 that can be divided by 6, 8, or both. Now, to do this, we must as to how many are divisible by 6 and how many are multiples of 8.

The closest number to 100 that is divisible by 6 is 102. 498 is the multiple of 6 closest to 500. To find the number of multiple of 6 from 102 to 498, we have

$n = \frac{498-102}{6} + 1$
$n = 67$

We can use the same approach, to find the number of integers that are divisible by 8 between 100 and 500.

$n = \frac{496-104}{8} + 1$
$n = 50$

That means there are 67 integers that are divisible by 6 and 50 integers divisible by 8. Remember that 6 and 8 share a common multiple of 24. That means the numbers 24, 48, 72, 96, etc are included in both lists. As shown below, there are 16 numbers that are multiples of 24.

$n = \frac{480-120}{24} + 1$
$n = 16$

Since we counted them twice, we subtract the number of integers that are divisible by 24 and have a final total of 67 + 50 - 16 = 101. Hence there are 101 integers that are divisible by 6, 8, or both.

Answer: 101

8 0

2 years ago

If D is an n × n diagonal matrix with entries dii, then det D = d11d22 ∙ ∙ ∙ dnn. Verify this theorem for 2 × 2 matrices.

nadya68 [22]

Answer:

Verified

Step-by-step explanation:

Let the diagonal matrix D with size 2x2 be in the form of

$\left[\begin{array}{cc}a&0\\0&d\end{array}\right]$

Then the determinant of matrix D would be

det(D) = a*d - 0*0 = ad

This is the product of the matrix's diagonal numbers

So the theorem is true for 2x2 matrices

8 0

2 years ago