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blsea [12.9K]
4 years ago
12

Divide the polynomials.

Mathematics
1 answer:
Mnenie [13.5K]4 years ago
3 0

Answer:

\dfrac{3x^3+x-11}{x+1}=3x^2-3x+4-\dfrac{15}{x+1}

Step-by-step explanation:

We want to determine the result of the quotient: \dfrac{3x^3+x-11}{x+1}

We follow the procedure of long division which is set out int he table below.

\left|\begin{array}{c|c}&3x^2-3x+4\\-----&-----\\x+1&3x^3+x-11\\Subtract&-(3x^3+3x^2)\\&------\\&-3x^2+x-11\\Subtract&-3x^2-3x\\&------\\&4x-11\\Subtract&4x+4\\&------\\&-15\end{array}\right|

Therefore:

\dfrac{3x^3+x-11}{x+1}=3x^2-3x+4-\dfrac{15}{x+1}

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