Question

Divide the polynomials.

Answer 1

Answer:

$\dfrac{3x^3+x-11}{x+1}=3x^2-3x+4-\dfrac{15}{x+1}$

Step-by-step explanation:

We want to determine the result of the quotient: $\dfrac{3x^3+x-11}{x+1}$

We follow the procedure of long division which is set out int he table below.

$\left|\begin{array}{c|c}&3x^2-3x+4\\-----&-----\\x+1&3x^3+x-11\\Subtract&-(3x^3+3x^2)\\&------\\&-3x^2+x-11\\Subtract&-3x^2-3x\\&------\\&4x-11\\Subtract&4x+4\\&------\\&-15\end{array}\right|$

Therefore:

$\dfrac{3x^3+x-11}{x+1}=3x^2-3x+4-\dfrac{15}{x+1}$