Hey! I know this is a bit late, but I realized I had the same question! Here is the answer to the question ;3Hope I helped! :D
Coin 1:The top box on the coin 1 section is QThe bottom box on the coin 1 section isNCoin 2:The first box on coin 2 is NThe second box is QThe third is QThe final box is N !Good luck~!
D) Daniel’s Brick
This is because it has the most bricks close to 2.5 inches.
Answer:
5in x 10in
Step-by-step explanation:
Solution:
1. You have to assume that the ring will land on the board and as a result, just focus on one rectangle of the board since they are all the same size.
2. For the ring to land entirely inside the rectangle, the center of the ring needs to be 1.5 inches inside the border (radius is 1.5 inches), so the "winning rectangle" will have dimensions:
L = (x - 2(1.5)) = x - 3
w = (2x - 2(1.5)) = 2x-3.
3. Now, we will set up and solve our geometric probability equation. The winning rectangle's area of (x-3)*(2x-3) divided by the total rectangle's area of x*(2x) = 28%
(2x-3)*(x-3)/(2x^2) = .28
2x^2 - 9x + 9 = .56x^2
1.44x^2 - 9x + 9 = 0
4 . Now you can plug that in the quadratic formula and get the solutions x = 1.25 or 5. However, it cannot by 1.25 because that is too small of a dimension for the the circle with diameter of 3 to fit in, the answers has to be 5.
5. As a result, the dimensions of the rectangles are 5in x 10in.
Answer:
y=−2/3x+3
Step-by-step explanation:
I graphed the point and the equation given below. I used the same slope in the new equation as the original equation. The y-intercept is 3 because the line goes through (0,3).
