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tekilochka [14]
3 years ago
13

Check MyAnswer Please!!!

Mathematics
1 answer:
jok3333 [9.3K]3 years ago
5 0
The equation x^2-9y^2=900 <span>defines a hyperbolic cylinder.
</span>
1. Divide the equation x^2-9y^2=900  by 900:
\dfrac{x^2}{900} - \dfrac{y^2}{100} =1.
This is the equation of conic section when z=0 (or z=const) and that is hyperbola equation.

2. To find the domain and the range you should express y:
\dfrac{y^2}{100} =\dfrac{x^2}{900} - 1 \\   \\ y^2= \dfrac{x^2}{9} -100 \\   \\ y=\pm  \sqrt{\dfrac{x^2}{9} -100}.
Since you have square root, 
\dfrac{x^2}{9} -100\ge 0 \\ x^2-900\ge 0 \\ (x-30)(x+30)\ge 0 \\ x\in(-\infty,-30)\cup (30,\infty). This is the domain, the range is y\in (-\infty,\infty).
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