Find the volumen of the semisphere and subtract the volumes of the two cylinders
1) Volume of the semisphere:
[1/2] (4/3)π(r^3) =[ 2π(1.5m)^3 ]/3 = 7.0686 m^3
2) Volumen of the cylinders:π(r^2)h
a) π(0.75/2m)^2 (1.75m) = 0.7731 m^3
b) π(1/2m)^2 (1.25m) = 0.9818 m^3
3) 7.0686 m^3 - 0.7731 m^3 - 0.9818m^3 = 5.3137 m^3
Answer: 5.3 m^3
Y + 4x = 8
y = 8 - 4x
substitute 8 - 4x for y in the other equation.
5x + 2(8 - 4x) = 13
5x + 16 - 8x = 13
-3x = -3
x = 1
y = 8 - 4(1) = 4
Add 2x^2 to both sides
7x^2-2x-6=9x
Subtract 9x from both sides
7x^2-11x-6=0
Factor by using slip and slide
x^2-11x-42
(x-14)(x+3)
(x-14/7)(x+3/7)
(x-2)(7x+3)
Then use the Zero Product Property to find roots
x-2=0
x=2
7x+3=0
7x=-3
x=-3/7
Final answer: x=-3/7, x=2
Answer: No
Step-by-step explanation:
I took a test and this answer was correct.
The answer the this is 0.23 pounds per container
