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Brrunno [24]
3 years ago
8

On his way out to meet a friend for lunch, David realized that his financial record was not up to date. He notices that he forgo

t to record three transactions. The first transaction was on August 2nd in the amount of $12.32, another transaction on that same day in the amount or $52.34, and finally a transaction on August 8th in the amount of $85.35. Determine David's balance carried forward for the 8th of August using the table below and the information provided. A check register. The Balance on August fifth is 1,049 dollars and 16 cents. a. $975.32 b. $899.15 c. $1,049.16 d. $848.84
Mathematics
1 answer:
Firlakuza [10]3 years ago
7 0

Answer:

b

Step-by-step explanation:

add the three numbers together then minus from the main total

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The area of a rectangular parking lot is represented by A = 6x^2 − 19x − 7 If x represents 15 m, what are the length and width o
Mekhanik [1.2K]

Answer:

The length and width of the parking lot are \frac{46}{3} meters and \frac{23}{2} meters, respectively.

Step-by-step explanation:

The surface formula (A) for the rectangular parking lot is represented by:

A = w\cdot l

Where:

w - Width of the rectangle, measured in meters.

l - Length of the rectangle, measured in meters.

Since, surface formula is a second-order polynomial, in which each binomial is associated with width and length. If A = 6\cdot x^{2}-19\cdot x -7, the factorized form is:

A = \left(x-\frac{7}{2}\,m \right)\cdot \left(x+\frac{1}{3}\,m \right)

Now, let consider that w = \left(x-\frac{7}{2}\,m \right) and l = \left(x+\frac{1}{3}\,m \right), if x = 15\,m, the length and width of the parking lot are, respectively:

w =\left(15\,m-\frac{7}{2}\,m \right)

w = \frac{23}{2}\,m

l =\left(15\,m+\frac{1}{3}\,m \right)

l = \frac{46}{3}\,m

The length and width of the parking lot are \frac{46}{3} meters and \frac{23}{2} meters, respectively.

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