Well, variables are stuff like x and y because they can represent a number. They are variable in an equation. so if you have (3x^3)+(5X^2)+Y+9 then your variables are x X and Y (im assuming the capital X is there and not a typo) if that was a typo and meant to be lowercase, then its just a 2 variable with the x and y
Answer:
360 mi/h
Step-by-step explanation:
The speed for the outbound trip was ...
speed = distance/time = (715 mi)/(2 1/6 h) = 330 mi/h
The inbound speed was ...
(715 mi)/(1 5/6 h) = 390 mi/h
The airspeed of the plane is the average of these two ground speeds, so is ...
(330 +390)/2 = 360 . . . . mi/h
I’m pretty sure the answer is C
<span>-16x^3+4x=0
-4x(4x^2 - 1) = 0
-4x(2x+1)(2x - 1) = 0 (factor using a^2 - b^2 = (a+b)(a-b))
-4x = 0; x =0
2x +1 = 0;x = -1/2
2x - 1 =0; x = 1/2
answer: x = 0, x = 1/2 and x = -1/2</span>
BC² = 11² + 11²
BC² = 121 + 121
BC² = 242
BC = √242
BC = 11√2
Answer: 11√2