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Butoxors [25]
3 years ago
7

WILL GIVE BRAINLY 3RD GRADE What is 1 + 2 + 3 times 78

Mathematics
2 answers:
olya-2409 [2.1K]3 years ago
7 0

Answer:

468

Step-by-step explanation:

Stolb23 [73]3 years ago
7 0

Answer:

237

Step-by-step explanation:

This is written as 1+2+(3x78)

=3+234

=237

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10 points! How could you correctly rewrite the equation 4(5 + 3) = 2(22 – 6) using the distributive property?
atroni [7]
D.
4x5 + 4x3 = 2x22 - 2x6
20+12=44-12
6 0
3 years ago
Read 2 more answers
3.14*16.8*16.8*16.9
vitfil [10]

Answer: 3.14 *16.8*16.8*16.9=14977.3478

14977.3478= 14,977.35

6 0
3 years ago
Determine what type of model best fits the given situation:
lyudmila [28]

Let value intially be = P

Then it is decreased by 20 %.

So 20% of P = \frac{20}{100} \times P = 0.2P

So after 1 year value is decreased by 0.2P

so value after 1 year will be = P - 0.2P (as its decreased so we will subtract 0.2P from original value P) = 0.8P-------------------------------------(1)

Similarly for 2nd year, this value 0.8P will again be decreased by 20 %

so 20% of 0.8P = \frac{20}{100} \times 0.8P = (0.2)(0.8P)

So after 2 years value is decreased by (0.2)(0.8P)

so value after 2 years will be = 0.8P - 0.2(0.8P)

taking 0.8P common out we get 0.8P(1-0.2)

= 0.8P(0.8)

=P(0.8)^{2}-------------------------(2)

Similarly after 3 years, this value P(0.8)^{2} will again be decreased by 20 %

so 20% of P(0.8)^{2}  \frac{20}{100} \times P(0.8)^{2} = (0.2)P(0.8)^{2}

So after 3 years value is decreased by (0.2)P(0.8)^{2}

so value after 3 years will be = P(0.8)^{2}   - (0.2)P(0.8)^{2}

taking P(0.8)^{2} common out we get P(0.8)^{2}(1-0.2)

P(0.8)^{2}(0.8)

P(0.8)^{3}-----------------------(3)

so from (1), (2), (3) we can see the following pattern

value after 1 year is P(0.8) or P(0.8)^{1}

value after 2 years is P(0.8)^{2}

value after 3 years is P(0.8)^{3}

so value after x years will be P(0.8)^{x} ( whatever is the year, that is raised to power on 0.8)

So function is best described by exponential model

y = P(0.8)^{x} where y is the value after x years

so thats the final answer

3 0
3 years ago
Write the following sets in the tabular form A<br><img src="https://tex.z-dn.net/?f=%28x.2x%20%2B%203%20%3D%2011%29" id="TexForm
MrRissso [65]
2x=11-3
2x=8
Simplify 8/2
=4
7 0
3 years ago
All four B points are equidistant from points A and C. Are they all midpoints of AC? Justify your answer.
Rina8888 [55]

Answer:

No

Step-by-step explanation:

For a point to be the midpoint of a line segment, it must bisect it into two equal segments and be on the line segment (hence, colinear with the endpoints). All four B points are equidistant from points A and C, but aren’t colinear with A and C. Therefore, they aren’t all midpoints of line segment AC.

I hope this helps! :)

5 0
3 years ago
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