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Strike441 [17]
3 years ago
8

Can someOne plz help answer these questions lol (only if u know how to do this) thanks :3

Mathematics
2 answers:
klio [65]3 years ago
8 0

Answer: The stem-and-leaf plot is shown below in the attached image.

=============================================================

Explanation

The given data set is:

40, 27, 17, 43, 47, 33, 26, 58, 49, 48, 35

64, 61, 54, 74, 43, 83, 61, 57, 34

Let's sort the values from smallest to largest

17, 26, 27, 33, 34, 35, 40, 43, 43, 47, 48, 49, 54, 57, 58, 61, 61, 64, 74, 83

The stems are the tens digit of each value. The stems used are: 1, 2, 3, 4, 5, 6, 7, and 8. The stems will go along the first column (along the left side) in the table.

The leaves represent the units digit of each value.

For example, the value 47 has a stem of 4 and a leaf of 7. At the top or bottom of your stem-and-leaf plot, you could have a key that says "4 | 7 means 47". The vertical line indicates the separation of stem and leaf.

For each stem row, sort the leaves from smallest to largest. You should get what you see in the table below. The horizontal spacing between each leaf is optional, and I find it's handy to easily read that portion of the table. Though your teacher or math book may remove those spaces entirely.

Also optional are horizontal grid lines to separate the stems.

Butoxors [25]3 years ago
7 0

Answer:

the answer is in the photo. :)

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Andrei [34K]

Answer:

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Step-by-step explanation:

The standard form of an equation of a circle:

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The midpoint of a diameter is a center of a circle.

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\left(\dfrac{x_1+x_2}{2},\ \dfrac{y_1+y_2}{2}\right)

Substitute:

x=\dfrac{-8+(-4)}{2}=\dfrac{-12}{2}=-6\\\\y=\dfrac{-6+(-14)}{2}=\dfrac{-20}{2}=-10

We have h = -6 and k = -10.

The radius is the distance between a center and the point on a circumference of a circle.

The formula of a distance between two points:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Substitute (-6, -10) and (-8, -6):

r=\sqrt{(-8-(-6))^2+(-6-(-10))^2}=\sqrt{(-2)^2+4^2}=\sqrt{4+16}=\sqrt{20}

Finally we have

(x-(-6))^2+(y-(-10))^2=(\sqrt{20})^2\\\\(x+6)^2+(y+10)^2=20

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