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Strike441 [17]
3 years ago
8

Can someOne plz help answer these questions lol (only if u know how to do this) thanks :3

Mathematics
2 answers:
klio [65]3 years ago
8 0

Answer: The stem-and-leaf plot is shown below in the attached image.

=============================================================

Explanation

The given data set is:

40, 27, 17, 43, 47, 33, 26, 58, 49, 48, 35

64, 61, 54, 74, 43, 83, 61, 57, 34

Let's sort the values from smallest to largest

17, 26, 27, 33, 34, 35, 40, 43, 43, 47, 48, 49, 54, 57, 58, 61, 61, 64, 74, 83

The stems are the tens digit of each value. The stems used are: 1, 2, 3, 4, 5, 6, 7, and 8. The stems will go along the first column (along the left side) in the table.

The leaves represent the units digit of each value.

For example, the value 47 has a stem of 4 and a leaf of 7. At the top or bottom of your stem-and-leaf plot, you could have a key that says "4 | 7 means 47". The vertical line indicates the separation of stem and leaf.

For each stem row, sort the leaves from smallest to largest. You should get what you see in the table below. The horizontal spacing between each leaf is optional, and I find it's handy to easily read that portion of the table. Though your teacher or math book may remove those spaces entirely.

Also optional are horizontal grid lines to separate the stems.

Butoxors [25]3 years ago
7 0

Answer:

the answer is in the photo. :)

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valentinak56 [21]

45 dimes and 93 nickels were in bank

<em><u>Solution:</u></em>

Let "n" be the number of nickels

Let "d" be the number of dimes

We know that,

value of 1 nickel = $ 0.05

value of 1 dime = $ 0.10

<em><u>Given that There are three more than twice as many nickels as there are dimes</u></em>

Number of nickels = 3 + 2(number of dimes)

n = 3 + 2d ---- eqn 1

<em><u>Also given that coin bank that excepts only nickels and dimes contains $9.15</u></em>

number of nickels x value of 1 nickel + number of dimes x value of 1 dime = 9.15

n \times 0.05 + d \times 0.10 = 9.15

0.05n + 0.10d = 9.15  ---- eqn 2

<em><u>Let us solve eqn 1 and eqn 2</u></em>

Substitute eqn 1 in eqn 2

0.05(3 + 2d) + 0.10d = 9.15

0.15 + 0.1d + 0.10d = 9.15

0.2d = 9

<h3>d = 45</h3>

From eqn 1

n = 3 + 2(45)

n = 3 + 90 = 93

<h3>n = 93</h3>

Thus 45 dimes and 93 nickels were in bank

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