Can’t help if there’s no figure
The question is incomplete. Here is the complete question.
As a part of city building refurbishment project, architects have constructed a scale model of several city builidings to present to the city commission for approval. The scale of the model is 1 inch = 9 feet.
The model includes a new park in the center of the city. If the dimensions of the park in the model are 9 inches by 17 inches, what are the actual dimensions of the park?
Answer: 81 feet by 153 feet
Step-by-step explanation: <u>Unit</u> <u>Scale</u> is a ratio comparing actual dimensions of an object to the dimensions of model representing the actual object.
In the refurbishment project, the unit scale is given by
1 inch = 9 feet
So, the dimensions of the new park in actual dimensions would be
1 inch = 9 feet
9 inches = x
x = 9.9
x = 81 feet
1 inch = 9 feet
17 inches = y
y = 17.9
y = 153 feet
The actual dimensions of the new park are 81 feet by 153 feet.
Sine 35 degrees = x / 20
x = sine 35 degrees * 20
x = .57358 * 20
x = 11.4716
Zenitsu from Demon Slayer
Answer:
6; 22; 20 (ft.)
Step-by-step explanation:
1) if the length of the each side are: n; 4n-2 and 4n-4, then the expression of the perimeter can be written: P=n+4n-2+4n-4 or P=9n-6.
2) if according to the condition perimeter is 48 (ft.), then
9n-6=P; ⇔ 9n-6=48; n=6.
3) if n=6, then the required lengths of the sides are:
n=6 (ft.);
4n-2=22 (ft.);
4n-4=20 (ft.)
