The trigonometric function's formula, which simulates the torque (tau) that the weight applied t minutes after Thomas attached it is

The angular speed of the minutes hand is
rad/min
Following the application of weight, the torque as a function of time t is,


<h3>
What is torque ?</h3>
Torque, which is also known as the moment of a force, is the propensity of a force to rotate the body to which it is applied. Force (F) x Distance (r) = Torque is how torque is calculated. The distance (r) between the pivot point and the force's action point. A vector quantity is a torque. As a vector quantity, torque always has a direction that is perpendicular to the plane that contains the vectors of force and displacement.
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Answer:
x = 4y+28
Step-by-step explanation:
x/4 -7 = y
Solve for x
Add 7 to each side
x/4 -7+7 = y+7
x/4 = (y+7)
Multiply each side by 4
x/4*4 = 4(y+7)
x = 4y+28
Answer:
x+2
Step-by-step explanation:
if a to the power of b is equal to x then a to the power of b +2 is x+2
The given function is

According to this function, the starting height of the rocket is 20 feet because that's the initial condition of the problem stated by the independent term.
Additionally, we find the maximum height by calculating the vertex of the function V(h,k).

Where a = -16 and b = 300.

Then, we find k by evaluating the function

Hence, the maximum height is 1426.25 feet.
At last, to know the time need to hit the ground, we just use h=9.375 and we multiply it by 2

Hence, the rocket hits the ground after 18.75 seconds.
Option C
The distance of a spin of one full rotation is 31.4 feet
<em><u>Solution:</u></em>
Given that,
A circular merry-go-round has a radius of 5 feet
Radius = 5 feet
We have to find the distance of spin for one full rotation
Distance covered in 1 full of rotation is equal to circumference of circle
<em><u>The circumference of circle is given as:</u></em>

Where "r" is the radius

Thus the distance of a spin of one full rotation is 31.4 feet