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Bumek [7]
3 years ago
5

If you could help that would be amazing!

Mathematics
2 answers:
vaieri [72.5K]3 years ago
8 0

Answer:

Step-by-step explanation:

Your answer is d

nevsk [136]3 years ago
5 0
Unknown side = (25^2-5^2)^.5 = 24.5

Using the Pythagorean theorem
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Help please ASAP!!!!!!
kobusy [5.1K]

Answer:

y=( )-2     y=2

Step-by-step explanation:

y=mx+b

6 0
3 years ago
Read 2 more answers
Create the equation of a line that perpendicular to 2y=14+2/3x and passes through the point (-2,8).
riadik2000 [5.3K]

Answer:

y = - 3x + 2

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Rearrange 2y = 14 + \frac{2}{3} x into this form

Divide all terms by 2

y = 7 + \frac{1}{3} x ← in slope- intercept form

with slope m = \frac{1}{3}

Given a line with slope m then the slope of a line perpendicular to it is

m_{perpendicular} = - \frac{1}{m} = - \frac{1}{\frac{1}{3} } = - 3, hence

y = - 3x + c ← is the partial equation of the perpendicular line

To find c substitute (- 2, 8) into the partial equation

8 = 6 + c ⇒ c = 8 - 6 = 2

y = - 3x + 2 ← equation of perpendicular line

4 0
3 years ago
What is the value of x?
Goshia [24]

Answer:

value of x is 20

Step-by-step explanation:

If u got any doubt regarding this u can ask anytime :)

3 0
3 years ago
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Suppose you have $16,000 to invest in three stocks, A, B, and C. Stock A is a low-risk stock that has expected returns of 4%. St
podryga [215]

To solve this problem, let us say that:

money invested in stock A = A

money invested in stock B = B

money invested in stock C = C

The given problem states that:

C = A * (1 / 4) = 0.25 A

B = A * (1 / 2) = 0.50 A

It was stated that we only have $16,000 to invest. Therefore:

A + B + C = 16,000

Substituting values of C and B in terms of A:

A + 0.50 A + 0.25 A = 16,000

1.75 A = 16,000

A = $9,142.86

So C and B is:

C = 0.25 (9142.86)
C = $2285.71

 

B = 0.50 (9142.86)

B = $4571.43 

5 0
4 years ago
Read 2 more answers
Stuck on two. Plz help. Pre-all is hard
algol [13]
Gncgbvcrvbshj hnctvvdf
7 0
3 years ago
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