Complete Question:
Emily and Zach have two different polynomials to multiply: Polynomial product A: (4x2 – 4x)(x2 – 4) Polynomial product B: (x2 + x – 2)(4x2 – 8x) They are trying to determine if the products of the two polynomials are the same. But they disagree about how to solve this problem.
Answer:
Step-by-step explanation:
<em>See comment for complete question</em>
Given
Required
Determine how they can show if the products are the same or not
To do this, we simply factorize each polynomial
For, Polynomial A: We have:
Factor out 4x
Apply difference of two squares on x^2 - 4
For, Polynomial B: We have:
Expand x^2 + x - 2
Factorize:
Factor out x + 2
Factor out 4x
Rearrange
The simplified expressions are:
and
Hence, both polynomials are equal
Substitute (-1)3-(-1)+(-1)0
multiply (-3)+1+0
simplify. -2
Final Answer: -2
Answer:
The answer is CANNOT (option b)
Step-by-step explanation:
<h2>
Answer:</h2><h2>
The actual height of the building = 36 feet.</h2>
Step-by-step explanation:
By blue print conversion,
2 inches = 8 feet
Therefore, 1 inch = 
= 4 feet
1 inch = 4 feet
The height of the building on the blueprint = 9 inches
The actual height of the building = 9 * 4 = 36 feet.
Answer:
8,996,734,079 numbers
Step-by-step explanation:
First let's find the number of ten-digit numbers.
The maximum ten-digit number is 9,999,999,999 and the minimum is 1,000,000,000. So the number of ten-digit numbers is:
Now, to find the number of ten-digit numbers with at least two equal digits, we can find the number of ten-digit numbers with all digits different, and then subtract this amount from the total ten-digit numbers.
To find the number of ten-digit numbers with all digits different, we can use the following logic:
The first digit can have 9 different values (0 not included), the second can also have 9 (one digit used), then the third can have 8 (two digits used), the fourth can have 7, and so on. So we have that:
Then the number of ten-digit numbers with at least two equal digits is:
