Answer:
(I attach your complete question in the picture below)
The apparent frequency would be
f' = 493.26 Hz
Step-by-step explanation:
This a Doppler's effect problem. This effects produces a slight change in the frequency of a traveling wave, due to the effect of the velocity of the receiver (observer).
The formula used to describe the change, as both vehicles are moving away of each other:
f' = [ (Vwave + Vobserver) / (Vwave + Vsource ) ]*f
Where
Vwave = 340 m/s ( speed of sound)
Vobserver = 18.6 m/s (observer = car)
Vsource = 23.5 m/s (speed of the ambulance = source)
f = 500 Hz (frequency of the sound)
We just need to substitute in the equation
f' = [(340+ 18.6) / (340+ 23.5)] * 500 Hz
f' = [0.9865] * 500 Hz = 493.26 Hz
f' = 493.26 Hz
Answer: |x-5|
Step-by-step explanation:
I dont know how to exlplain it
<em>Greetings from Brasil...</em>
According to the statement of the question, we can assemble the following system of equation:
X · Y = - 2 i
X + Y = 7 ii
isolating X from i and replacing in ii:
X · Y = - 2
X = - 2/Y
X + Y = 7
(- 2/Y) + Y = 7 <em>multiplying everything by Y</em>
(- 2Y/Y) + Y·Y = 7·Y
- 2 + Y² = 7X <em> rearranging everything</em>
Y² - 7X - 2 = 0 <em>2nd degree equation</em>
Δ = b² - 4·a·c
Δ = (- 7)² - 4·1·(- 2)
Δ = 49 + 8
Δ = 57
X = (- b ± √Δ)/2a
X' = (- (- 7) ± √57)/2·1
X' = (7 + √57)/2
X' = (7 - √57)/2
So, the numbers are:
<h2>
(7 + √57)/2</h2>
and
<h2>
(7 - √57)/2</h2>