Question

Amira is solving the equation x2 – 6x = 1. Which value must be added to both sides of the equation to make the left side a perfect-square trinomial?

Answer 1

I hope this helps you

Answer 2

Answer:

We have to add 9 on both sides of the equation.

Step-by-step explanation:

The given equation is $x^2 - 6x = 1$

Let's identify the value of "b" by comparing the general form of quadratic equation $ax^2 + bx + c = 0$

Here the value of b = -6

To make it perfect square trinomial, we have to divide b value by 2 and make it square. Then we have to add it on both side of the equation.

(b/2) = (-6/2)^2 = (-3)^2 = -3*-3 = 9

So we need to add 9 on both sides of the equation in order to make it perfect square.

$x^2 - 6x + 9 = 1 + 9\\(x -3)^2 = 10$