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Brrunno [24]
4 years ago
12

Amira is solving the equation x2 – 6x = 1. Which value must be added to both sides of the equation to make the left side a perfe

ct-square trinomial?

Mathematics
2 answers:
likoan [24]4 years ago
5 0
I hope this helps you

NeTakaya4 years ago
5 0

Answer:

We have to add 9 on both sides of the equation.

Step-by-step explanation:

The given equation is x^2 - 6x = 1

Let's identify the value of "b" by comparing the general form of quadratic equation ax^2 + bx + c = 0

Here the value of b = -6

To make it perfect square trinomial, we have to divide b value by 2 and make it square. Then we have to add it on both side of the equation.

(b/2) = (-6/2)^2 = (-3)^2 = -3*-3 = 9

So we need to add 9 on both sides of the equation in order to make it perfect square.

x^2 - 6x + 9 = 1 + 9\\(x -3)^2 = 10

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