Explanation:
Technology should not be used to teach in school as it can lead to distractions. With kids wanting to explore other sights, cheating, and communicating with others. Also, it can be expensive to purchase the technology for everyone as it can be a major investment with hundreds or thousands going into it. Technology also requires a lot of training by having to adapt lessons compatible with the systems and making sure the software is secure.
Answer:
player vs anonymous players
Answer:
def select_short_strings(string_list):
new_list = []
for s in string_list:
if len(s) < 20:
new_list.append(s)
return new_list
lst = ["apple", "I am learning Python and it is fun!", "I love programming, it is easy", "orange"]
print(select_short_strings(lst))
Explanation:
- Create a function called <em>select_short_strings</em> that takes one argument <em>string_list</em>
Inside the function:
- Initialize an empty list to hold the strings that are less than 20
- Inside the loop, check the strings inside <em>string_list</em> has a length that is smaller than 20. If found one, put it to the <em>new_list</em>.
- When the loop is done, return the <em>new_list</em>
- Create a list to check and call the function
Complete Question:
Recall that with the CSMA/CD protocol, the adapter waits K. 512 bit times after a collision, where K is drawn randomly. a. For first collision, if K=100, how long does the adapter wait until sensing the channel again for a 1 Mbps broadcast channel? For a 10 Mbps broadcast channel?
Answer:
a) 51.2 msec. b) 5.12 msec
Explanation:
If K=100, the time that the adapter must wait until sensing a channel after detecting a first collision, is given by the following expression:
The bit time, is just the inverse of the channel bandwidh, expressed in bits per second, so for the two instances posed by the question, we have:
a) BW = 1 Mbps = 10⁶ bps
⇒ Tw = 100*512*(1/10⁶) bps = 51.2*10⁻³ sec. = 51.2 msec
b) BW = 10 Mbps = 10⁷ bps
⇒ Tw = 100*512*(1/10⁷) bps = 5.12*10⁻³ sec. = 5.12 msec
