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Paladinen [302]
3 years ago
6

NEED IT FAST PLEASE Which is the graph of the linear equation x – 2y = 6? On a coordinate plane, a line goes through points (neg

ative 6, 0) and (0, 3). On a coordinate plane, a line goes through points (0, negative 3) and (6, 0). On a coordinate plane, a line goes through points (negative 6, 0) and (0, negative 3). On a coordinate plane, a line goes through points (0, 3) and (6, 0).
Mathematics
2 answers:
Anastasy [175]3 years ago
8 0

Answer:

B or graph 2

Step-by-step explanation:

when y = 0 then x = 6

when x = 0 then y = -3

find those points

hope this helps

koban [17]3 years ago
6 0

Y= (x-6)/2. Plug that for of first equation into;

Answer:

Math is fun dot com. All one word. (With .)

For other straight lines, I’m assuming you are supposed to graph the intersections, just use the two point form to get the rise and run. The rise / run is the slope. Usually called ‘m’ in formula form. Plug each Straight line formula into the Same web page above and it will graph the line for you. Be sure each line is in the [Y = mX+b ]

Format. Y is the up, X is the over, m is the slope. (Change in Y divided by change in X) (like stairs), and ‘b’ is the Y intercept. That means where the line crosses the Y (up) axis.

Step-by-step explanation:

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What plus 150 equals to 180
zzz [600]

Answer:

30

Step-by-step explanation:

150+30=180

Hope This Helps!!

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5 0
3 years ago
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Circle O, with center (x, y) passes through the points A(0, 0), B(-3, 0), and C(1, 2). Find the coordinates of the center of the
KonstantinChe [14]

Answer:

The center of the circle is

(-\frac{3}{2},2)

Step-by-step explanation:

Let the equation of the circle be

x^2+y^2+2ax+2by+c=0, where (-a,-b) is the center of this circle.

The points lying the circle must satisfy the equation of this circle.

A(0,0)

We substitute this point to get;

0^2+0^2+2a(0)+2b(0)+c=0

\implies c=0

B(-3,0)

(-3)^2+0^2+2a(-3)+2b(0)+c=0

\implies 9+0-6a+0+c=0

\implies -6a+c=-9

But c=0

\implies -6a=-9

\implies a=\frac{3}{2}

C(1,2)

1^2+2^2+2a(1)+2b(2)+c=0

1+4+2a+4b+c=0

2a+4b+c=-5

Put the value of 'a' and 'c' to find 'b'

2(\frac{3}{2})+4b+0=-5

3+4b+0=-5

4b=-5-3

4b=-8

b=-2

Hence the center of the circle is

(-\frac{3}{2},2)

8 0
3 years ago
Solve.
yarga [219]
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X < -423
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nydimaria [60]

Answer:

4000 + .06x ≥ 7000

Step-by-step explanation:

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3 years ago
If a=3 and b=5 then ab/15+a(6+7b)=
lilavasa [31]

Answer:155

Step-by-step explanation:

If a=3 and b=5 then

3•5/15+3•6+7•5=155

8 0
3 years ago
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