Answer: He ended up with about 1 pound less grapes
Step-by-step explanation:
2 bags of grapes weighing 5 and two-thirds pounds each will give a total weight of:
= 2 × 5 2/3
= 2 × 17/3
= 34/3
= 11 1/3 pounds
3 bags weighing 4 and one-fifth pounds each, will give a weight of:
= 3 × 4 1/5
= 3 × 21/5
= 63/5
= 12 3/5
He ended up buying lesser grapes. This was about 12 3/5 - 11 1/3 = 1 4/15 less. This means that he ended up with about 1 pound less grapes
Your question seems incomplete :-(
The formula is
(theta)/360 · 2(pi)r
theta is the given angle
r is radius of the circle
For this problem, we are going to use the <em>law of sines</em>, which states:

In this case, we have an angle and two sides, and we are trying to look for the third side. First, we have to find the angle which corresponds with the second side,
. Then, we can find the third side. Using the law of sines, we can find:

We can use this to solve for
:


Now, we can find
:

Using this, we can find
:


c is approximately 17.5.
Given:
radius of cone = r
height of cone = h
radius of cylinder = r
height of cylinder = h
slant height of cone = l
Solution
The lateral area (A) of a cone can be found using the formula:

where r is the radius and l is the slant height
The lateral area (A) of a cylinder can be found using the formula:

The ratio of the lateral area of the cone to the lateral area of the cylinder is:

Canceling out, we have:

Hence the Answer is option B