Answer:

Step-by-step explanation:
Composition of two functions f(x) and g(x) is represented by,
(fog)(x) = f[g(x)]
If a function is,
f(x) = (-6x - 8)² [where x ≤
]
Another function is the inverse of f(x),

Now composite function of these functions will be,
![(fof^{-1})(x)=f[f^{-1}(x)]](https://tex.z-dn.net/?f=%28fof%5E%7B-1%7D%29%28x%29%3Df%5Bf%5E%7B-1%7D%28x%29%5D)
= ![[-6(\frac{\sqrt{x}+8}{6})-8]^{2}](https://tex.z-dn.net/?f=%5B-6%28%5Cfrac%7B%5Csqrt%7Bx%7D%2B8%7D%7B6%7D%29-8%5D%5E%7B2%7D)
= ![[-\sqrt{x}+8-8]^2](https://tex.z-dn.net/?f=%5B-%5Csqrt%7Bx%7D%2B8-8%5D%5E2)
= 
= x
Therefore, 
4/5 ,8/10, 16/20,
You multiply both numbers with the same number.
For ex. 4×2=8 5×2=10 so we have 8/10
Answer:
Step-by-step explanation:
if these are diagonals ,then
area=(product of diagonals)/2
=(6*14)/2=42 ft²
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Answer:
A quadratic equation can be written as:
a*x^2 + b*x + c = 0.
where a, b and c are real numbers.
The solutions of this equation can be found by the equation:

Where the determinant is D = b^2 - 4*a*c.
Now, if D>0
we have the square root of a positive number, which will be equal to a real number.
√D = R
then the solutions are:

Where each sign of R is a different solution for the equation.
If D< 0, we have the square root of a negative number, then we have a complex component:
√D = i*R

We have two complex solutions.
If D = 0
√0 = 0
then:

We have only one real solution (or two equal solutions, depending on how you see it)