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Damm [24]
3 years ago
12

Write an equation of the direct variation that includes the point (6,-2)

Mathematics
1 answer:
olga55 [171]3 years ago
7 0

Answer:

y =  -  \frac{1}{3}x

Step-by-step explanation:

The equation of a direct variation is generally written as:

y = mx

Where m is the slope of the equation of the direct variation line.

We want a direct variation equation that contains (6,-2).

We substitute the x=6 and y=-2 to find m.

- 2 =  6m

Divide both sides by 6.

\frac{ - 2}{ 6}  =  \frac{6m}{ 6}

-  \frac{1}{3} = m

The required equation is

y =  -  \frac{1}{3}x

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The equation would be

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Since we don't know how big was your collection before, this would be the equation to solve it.

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Which algebraic expression is a polynomial with a degree of 5?
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The degree of a polynomial is the highest exponent or sum of exponents of the variables in the individual terms of a polynomial.

Looking at each the polynomial:

3x5 + 8x4y2 – 9x3y3 – 6y5: Degree is 6 (look at the 2nd and 3rd term)

2xy4 + 4x2y3 – 6x3y2 – 7x4: Degree is 5 (look at 1st, 2nd, and 3rd term)

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2xy4 + 4x2y3 – 6x3y2 – 7x4
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3 years ago
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Name the point of concurrency of the angle bisectors.<br> a. A<br> b. B<br> c. C<br> d. not shown
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The volume of an oblique pyramid with a square base is V units3 and the height is h units.Which expression represents the area o
melamori03 [73]

Answer: a) \dfrac{3V}{h}\ units^2

Step-by-step explanation:

We know that the volume of an oblique pyramid is given by :-

\text{Volume}=\dfrac{1}{3}\text{(Base Area x height) }

If the volume of an oblique pyramid with a square base is V units³ and the height is h units.

Then, we have

V=\dfrac{1}{3}\text{(Base Area x h) }

Multiply 3 on both sides , we get

3V=\text{(Base Area x h) }

Divide both sides by h , we get

\dfrac{3V}{h}=\text{Base Area }

i.e. \text{Base Area }=\dfrac{3V}{h}\ units^2

Hence, the expression represents the area of the base of the pyramid = \dfrac{3V}{h}\ units^2

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3 years ago
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Answer:

He can afford 5 large cheese pizzas.

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$40 ÷ $7.50 = 5.333333

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