Answer: fluffy = 33yrs
Spot = 19 yrs
Skampy = 39 yrs
Step-by-step explanation:
Let fluffy = x
Spot = y
Skampy =z
x + y + z = 91 -------1
x -14 =y ------2
z = x + 6 --------3
Put eqn 2 and 3 in eqn 1
x + x - 14 + x + 6 = 91
3x = 99
x = 33
y = 33-14= 19
z = 33+6 = 39
Since this is a problem of simple interest, then the interest earned will be based always on the principal amount which is 5000. So assuming that, lets also assume that the duration to get interest will be in years since that is the most commonly used duration anyway. So first, let's multiply 5000 with 0.075 to get the interest for the first year. So we will have 375. This means that we will be getting 375 interest every year. We can do trial an error method to get the number of years that will yield us to 6500. Through that, I was able to get 4 years. So 4 times 375 equals 1500 plus the original balance of 5000. It will take 4 years before your balance reaches 6500
Answer:
Peyton's account will have $13,842.18 after a year.
Step-by-step explanation:
Given that Peyton received $ 12,700 and decided to invest it for a year in an account that grants an interest of 8.8% per year, compounded semiannually, to determine the amount of money that will be in said account after the passage of one year, it is necessary to perform the following calculation:
X = 12,700 (1 + 0.088 / 2) ^ 1x2
X = 13,842.18
Therefore, after a year has passed, Peyton's account will be $ 13,842.18.
Answer:
18 pots.
Step-by-step explanation:
10/2 to get one of the longs. 5(2) to get the other one. 10.
8/4 to get one of the wides. 2(2) to get the other one. 4.
There are 4 corners so there are 4 extra pots. 4.
Add the numbers: 4+4+10. 18
Answer:

Step-by-step explanation:
we have
<em>The equation of the first line</em>
------> equation A
<em>The equation of the second line</em>
------> equation B
Solve the system of equations by elimination
Multiply equation A by -4 both sides
--------> equation C
Adds equation B and equation C

<em>Find the value of x</em>
substitute the value of y


Multiply by 3 both sides


therefore
The solution to the system of equations is the point 