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olchik [2.2K]
3 years ago
5

Enter the correct answer in the box. What is this expression in simplified form? 3\sqrt{88}

Mathematics
1 answer:
Ugo [173]3 years ago
4 0

Answer: 12\sqrt{5}

Step-by-step explanation:

3\sqrt{88}

88 can be rewritten as 8 x 10 and 8 can be rewritten as 2^2*2 making a 2 come out of the root.

3\sqrt{2^2*2*10}\\ 3*2\sqrt{2*10}\\6\sqrt{2*10}

10 can be rewritten as 2 x 5.

6\sqrt{2*2*5}

2*2 can also be rewritten as 2^2 making a 2 come out of the root.

6\sqrt{2^2*5}\\ 6*2\sqrt{5}\\ 12\sqrt{5}

We can't keep simplifying the root.

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Quadrilateral RJFT is similar to quadrilateral SYPA . JF=60 mm , AP=40 mm , and YP=25 mm . What is TF ?
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The two quadrilaterals are similar. Which means the ratios of respective sides of two quadrilaterals will be the same. 

So, for the given quadrilaterals, ratio of sides JF and TF of quadrilateral RJFT will be equal to the ratio of sides YP and AP of quadrilateral SYPA. Mathematically, we can write:

JF:TF = YP:AP \\  \\ &#10; \frac{JF}{TF} = \frac{YP}{AP}  \\  \\ &#10; \frac{60}{TF} = \frac{25}{40}  \\  \\ &#10;60* \frac{40}{25}=TF \\  \\ &#10;TF=96mm

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7 0
3 years ago
A manufacturer of golf equipment wishes to estimate the number of left-handed golfers. A previous study indicates that the propo
never [62]

Answer:

A sample of 997 is needed.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of 1 - \frac{\alpha}{2}.

The margin of error is of:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

A previous study indicates that the proportion of left-handed golfers is 8%.

This means that \pi = 0.08

98% confidence level

So \alpha = 0.02, z is the value of Z that has a p-value of 1 - \frac{0.02}{2} = 0.99, so Z = 2.327.  

How large a sample is needed in order to be 98% confident that the sample proportion will not differ from the true proportion by more than 2%?

This is n for which M = 0.02. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.02 = 2.327\sqrt{\frac{0.08*0.92}{n}}

0.02\sqrt{n} = 2.327\sqrt{0.08*0.92}

\sqrt{n} = \frac{2.327\sqrt{0.08*0.92}}{0.02}

(\sqrt{n})^2 = (\frac{2.327\sqrt{0.08*0.92}}{0.02})^2

n = 996.3

Rounding up:

A sample of 997 is needed.

3 0
3 years ago
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