Answer:
This is the answer of this question. Hope it helps.
Answer:
First choice V = 18,432π m^3; S = 2,304π m^2
Step-by-step explanation:
Start with the two formulas:
Volume of a circle:
![V = \dfrac{4}{3} \pi r^3](https://tex.z-dn.net/?f=%20V%20%3D%20%5Cdfrac%7B4%7D%7B3%7D%20%5Cpi%20r%5E3%20)
Surface area of a circle:
![S = 4 \pi r^2](https://tex.z-dn.net/?f=%20S%20%3D%204%20%5Cpi%20r%5E2%20)
Now use r = 24 m in each formula.
Volume:
![V = \dfrac{4}{3} \pi (24~m)^3](https://tex.z-dn.net/?f=%20V%20%3D%20%5Cdfrac%7B4%7D%7B3%7D%20%5Cpi%20%2824~m%29%5E3%20)
![V = \dfrac{4}{3} \pi (13,824~m^3)](https://tex.z-dn.net/?f=%20V%20%3D%20%5Cdfrac%7B4%7D%7B3%7D%20%5Cpi%20%2813%2C824~m%5E3%29%20)
![V = 18,432\pi~m^3](https://tex.z-dn.net/?f=%20V%20%3D%2018%2C432%5Cpi~m%5E3%20)
Surface area:
![S = 4 \pi r^2](https://tex.z-dn.net/?f=%20S%20%3D%204%20%5Cpi%20r%5E2%20)
![S = 4 \pi (24~m)^2](https://tex.z-dn.net/?f=%20S%20%3D%204%20%5Cpi%20%2824~m%29%5E2%20)
![S = 4 \pi (576~m^2)](https://tex.z-dn.net/?f=%20S%20%3D%204%20%5Cpi%20%28576~m%5E2%29%20)
![S = 2,304\pi ~m^2](https://tex.z-dn.net/?f=%20S%20%3D%202%2C304%5Cpi%20~m%5E2%20)
Answer: First choice V = 18,432π m^3; S = 2,304π m^2
Let the length of the race be d miles.
Race time for Pat = d/10
Race time for Kim = d/9
If we subtract 8 minutes from the time for Kim, the result will equal the time for Pat:
![\frac{d}{10}=\frac{d}{9}-\frac{8}{60}](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7B10%7D%3D%5Cfrac%7Bd%7D%7B9%7D-%5Cfrac%7B8%7D%7B60%7D)
This equation simplifies to:
![\frac{d}{10}=\frac{5d-6}{45}](https://tex.z-dn.net/?f=%5Cfrac%7Bd%7D%7B10%7D%3D%5Cfrac%7B5d-6%7D%7B45%7D)
Cross-multiplying we get:
45d = 50d -60
60 = 5d
d = 12 miles
Answer:you should help me with my problem and ill help you plzzzz
Step-by-step explanation:
The y int is 8 and the slope is 1/2