Answer:
I can't really see the question. Maybe the below will help anyway
Step-by-step explanation:
Use SOH CAH TOA to recall how the trig functions fit on a triangle
SOH: Sin(Ф)= Opp / Hyp
CAH: Cos(Ф)= Adj / Hyp
TOA: Tan(Ф) = Opp / Adj
Answer:
40/49
Step-by-step explanation:
probability that a point chosen at random in the given figure will be inside the larger circle and outside the smaller circle = ( area larger circle - area of smaller circle / area of larger circle )
area of a circle = πr² where r = radius
area of smaller circle :
radius = 6
==> plug in 6 for r
A = π(6)²
==> evaluate exponent
A = 36π
Area of larger circle :
Radius = 14
==> plug in 14 for r
A = π(14)²
==> evaluate exponent
A = 196π
We have probability = area larger circle - area of smaller circle / area of larger circle
area of larger circle = 196π
area of smaller circle = 36π
probability = (196π - 36π)/196π
==> subtract 36 from 196
probability = 160π/196π
==> simplify fraction and cancel out π
probability = 40/49
Answer:
A
Step-by-step explanation:
Given
x² + 6x + 4 = 0 ( subtract 4 from both sides )
x² + 6x = - 4
Solve using the method of completing the square
add ( half the coefficient of the x- term )² to both sides
x² + 2(3)x + 9 = - 4 + 9, that is
(x + 3)² = 5 ( take the square root of both sides )
x + 3 = ± 
( subtract 3 from both sides )
x = - 3 ± , thus
x = - 3 - → A
x = - 3 +
