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Allushta [10]
3 years ago
5

What is sqrt 192 in simplest form

Mathematics
1 answer:
jeka57 [31]3 years ago
4 0

Answer:

8√3.

Step-by-step explanation:

192 = 2 * 2 * 2 * 2 * 2 * 2 * 3

The square root of the multiple of the 6  2's is 2*2*2 = 8

so √192 = 8√3.

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Answer:

a) z = 1.645

b) The should sample at least 293 small claims.

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We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.9}{2} = 0.05

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.05 = 0.95, so z = 1.645, which means that the answer of question a is z = 1.645.

Now, find  the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

(b) If the group wants their estimate to have a maximum error of $12, how many small claims should they sample?

They should sample at least n small claims, in which n is found when

M = 12, \sigma = 124.88. So

M = z*\frac{\sigma}{\sqrt{n}}

12 = 1.645*\frac{124.88}{\sqrt{n}}

12\sqrt{n} = 205.43

\sqrt{n} = \frac{205.43}{12}

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n = 293

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