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3 years ago

Which function models the area of a rectangle with side lengths of 2x – 4 units and x + 1 units? What is the area when x = 3?

Mathematics

1 answer:

evablogger [386]3 years ago

3 0

Answer:

D. f(x) = 2x^2 − 2x − 4; A = 8

Step-by-step explanation:

The area of a rectangle is given by the formula length x wide.

In this case we have that the length is 2x -4 and the wide is x +1

Therefore, the area will be:

$A= (2x-4)(x+1)= 2x^2+2x-4x-4=2x^2-2x-4\\A= 2x^2-2x-4$

Now, when x = 3 we would have:

$A=2(3)^2-2(3)-4= 2(9)-6-4=18-10=8\\A=8$

Thus, the right answer is D.

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salantis [7]

Answer:

2 - $\sqrt{3}$

Step-by-step explanation:

Using the addition formula for tangent

tan(A - B) = $\frac{tanA-tanB}{1+tanAtanB}$ and the exact values

tan45° = 1 , tan60° = $\sqrt{3}$ , then

tan15° = tan(60 - 45)°

tan(60 - 45)°

= $\frac{tan60-tan45}{1+tan60tan45}$

= $\frac{\sqrt{3}-1 }{1+\sqrt{3} }$

Rationalise the denominator by multiplying numerator/ denominator by the conjugate of the denominator.

The conjugate of 1 + $\sqrt{3}$ is 1 - $\sqrt{3}$

= $\frac{(\sqrt{3}-1)(1-\sqrt{3}) }{(1+\sqrt{3})(1-\sqrt{3}) }$ ← expand numerator/denominator using FOIL

= $\frac{\sqrt{3}-3-1+\sqrt{3} }{1-3}$

= $\frac{-4+2\sqrt{3} }{-2}$

= $\frac{-4}{-2}$ + $\frac{2\sqrt{3} }{-2}$

= 2 - $\sqrt{3}$

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3 years ago

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photoshop1234 [79]

1 meter is greater then 83 cm Because if you divide it will be 0.83 and the differences will be 0.17

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3 years ago

4x - 4 - 8y + 8 - 5x + 1 =

SashulF [63]

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Solve the following linear programming problem by applying the simplex method to the dual problem.

Law Incorporation [45]

Answer:

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Subject to Constraints:

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Step-by-step explanation:

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3 years ago