B=1.4
Is the answer.
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3w +2 =7w
-3w -3w
2=4w
Divide each side by 4
1/2=w
Check your answer:
3 (1/2) + 2 = 7 (1/2)
(3/2) + (4/2) = (7/2)
(7/2) = (7/2)
Hope this helps.
Answer:
use logarithms
Step-by-step explanation:
Taking the logarithm of an expression with a variable in the exponent makes the exponent become a coefficient of the logarithm of the base.
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You will note that this approach works well enough for ...
a^(x+3) = b^(x-6) . . . . . . . . . . . variables in the exponents
(x+3)log(a) = (x-6)log(b) . . . . . a linear equation after taking logs
but doesn't do anything to help you solve ...
x +3 = b^(x -6)
There is no algebraic way to solve equations that are a mix of polynomial and exponential functions.
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Some functions have been defined to help in certain situations. For example, the "product log" function (or its inverse) can be used to solve a certain class of equations with variables in the exponent. However, these functions and their use are not normally studied in algebra courses.
In any event, I find a graphing calculator to be an extremely useful tool for solving exponential equations.
Answer:
₹ 4000
Step-by-step explanation:
Sarah's salary =₹ 30000
- one-tenth of her salary to an orphanage= 1/10*₹ 30000= ₹ 3000
- one-third of her salary is spent on food= 1/3*₹ 30000= ₹ 10000
- one-fourth of salary on rent and electricity =1/4*₹ 30000= ₹ 7500
- one-twentieth of her salary on the telephone= 1/12*₹ 30000= ₹ 2500
- donated some amount to the Prime Minister's relief fund = x
- She was left with ₹ 3000.
x= ₹ 30000- (₹ 3000+₹ 10000+₹ 7500+₹ 2500+₹ 3000)= ₹ 4000
The answer would be (-3+18) + (i +5i)
This is because changing the order of the numbers does not change the sum
