Find the value of x. x+35 4x

A square room has an area of 14,400 square

omeli [17]

Answer:

4 i think

Step-by-step explanation:

8 0

2 years ago

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The length of a rectangle is 2 inches more than its width. The perimeter of the rectangle is 24 inches. The equation 2x + 2(x +

alexandr1967 [171]

2x + 2(x + 2) = 24
2x + 2x + 4 = 24
4x = 24 - 4
4x = 20
x = 20/4
x = 5

The value of x that holds true for the equation is : x = 5.
So the width of the rectangle is 5 inches and the length is (x + 2 = 5 + 2) = 7 inches

7 0

3 years ago

Please help me I need help

ozzi

D. is your answer
4/x^2

hope it helps

7 0

3 years ago

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Consider the function f(x) = x² – 3x – 4 and complete parts (a) through (C). (a) Find f(a+h); f(a+h)-f(a) (b) Find (c) Find the

Artist 52 [7]

Answer:

(a)

$f(a+h)=a^{2} +2ah+h^{2} -3a-3h-4$

(b)

$f(a+h)-f(a)=2ah+h^{2} -3h$

(c)

$\frac{df(a+h)}{dx} \left \{ { \atop {a=7}} \right. =2h+11$

Step-by-step explanation:

(a)

Simply evaluate (a+h) in the function:

$f(a+h)=(a+h)^{2} -3(a+h)-4=a^{2} +2ah+h^{2} -3a-3h-4$

(b)

Evaluate (a) in the function:

$f(a)=a^{2} -3a-4$

Using the previous answers lets calculate f(a+h)-f(a)

$f(a+h)-f(a)=a^{2} +2ah+h^{2} -3a-3h-4-(a^{2} -3a-4)=2ah+h^{2} -3h$

(c) To find the rate of change of f(a+1) when a=7 we need to calculate its derivate at that point:

$\frac{df(a+h)}{dx} \left \{ { \atop {a=7}} \right. =2a+2h-3=2(7)+2h-3=2h+14-3=2h+11$

7 0

3 years ago

Let p = the product of all the odd integers between 500 and 598, and let q = the product of all the odd integers between 500 and

tia_tia [17]

$p=501\cdot503\cdot\cdots\cdot597$

$q=\underbrace{501\cdot503\cdot\cdots\cdot597}_p\cdot599\cdot601$

So we have $q=359,999p$ . Then

$\dfrac1p+\dfrac1q=\dfrac{359,999}{359,999p}+\dfrac1q=\dfrac{359,999+1}q=\dfrac{360,000}q$

and the answer is D.

4 0

3 years ago