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egoroff_w [7]
3 years ago
6

All the answers for 1 and 2

Mathematics
1 answer:
Anarel [89]3 years ago
4 0
Zarat Zim earns $240 
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Help plzzz someone solve it i need help
nekit [7.7K]
19° hope this helped!
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3 years ago
A rectangle's area is given by the expression 6n2-n+
Zolol [24]

Answer:

Length of rectangle:    2n - (1/3)  + 9/(3n)

Width of rectangle =  3n

Rectangle area  = A = 6 n^2  - n + 9

Step-by-step explanation:

Rectangle area  = A = 6 n^2  - n + 9

test what the roots are:    b^2 - 4ac  = (-1)^2 - 4*6*9 < 0  no real roots

-215 < 0  discriminant

(6 n^2  - n + 9)  / (3n) =

2n  -  (1/3)  +  9/(3n)

If the area is divided by 3n,  the quotient is  2n - (1/3) and the remainder is 9

8 0
3 years ago
Quadrilateral STWR is inscribed inside a circle as shown below. Write a proof showing that angles T and R are supplementary.
AlladinOne [14]

Observe the given figure.

Here, angle T and R are the inscribed angles.

And sum of inscribed angles is half of measure of intercepted arcs.

Since, the measure of intercepted arcs is 360 degrees.

Therefore, \angle T + \angle R = \frac{1}{2} \times 360 ^{\circ}

\angle T + \angle R = 180 ^{\circ}

Hence, the sum of the two angles is 180 degrees.

Therefore, these are the supplementary angles.

Therefore, angle T and angle R are supplementary angles.

Hence, proved.

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