Question

Hiii guys i need help with my homewrok lt="-9\leq 7-8x" align="absmiddle" class="latex-formula">

Answer 1

Answer:

The answer is x ≤ 2.

Step-by-step explanation:

Firstly, you have to move the unrelated term to the other side :

$- 9 \leqslant 7 - 8x$

$- 9 - 7 \leqslant - 8x$

$- 16 \leqslant - 8x$

Next you can solve it :

$- 8x \geqslant - 16$

$x \leqslant - 16 \div - 8$

$x \leqslant 2$

*Remember to change the symbol, when it is dividing by a negative value