If m ACD = 30 => m DCB = 60.
In triangle ACD:
AC^{2}+CB^{2}=AB^{2} => AB=
=32.
=> P=16+32+
=48 +
.
Answer is 60 U need to calculate carefully with brackets involving multiplication
To find the midpoint you find the average x and the average y values. The average of 1 and 9 is 5, and the average of 4 and 16 is 10. The midpoint would be (5,10).
Answer:
(7a-3a)+(2a-a)=16
4a+a or 1a =16
5a=16
5a/5=16/5
a =16/5 or a=3.2
Step-by-step explanation:
solving like terms or substract are same
you only have to find value of uknown value which was "a" question