Answer:
The cost of one rose bushes be $10 and the cost of shrubs $4.
Step-by-step explanation
Let us assume that the cost of rose bushes be x .
Let us assume that the cost of shrubs be y .
As given
Rob and Amy each improved their yards by planting rose bushes and shrubs.
They bought their supplies from the same store.
Rob spent $100 on 8 rose bushes and 5 shrubs.
Than the equation
8x + 5y = 100
Amy spent $112 on 8 rose bushes and 8 shrubs.
8x + 8y = 112
Than the two equation
8x + 5y = 100 and 8x + 8y = 112
Subtracting 8x + 5y = 100 from 8x + 8y = 112
8x - 8x + 8y - 5y = 112 - 100
3y = 12
y = $4
Put in the equation 8x + 5y = 100 .
8x + 5 × 4 = 100
8x + 20 = 100
8x = 100 - 20
8x = 80
x = $10
Therefore the cost of one rose bushes be $10 and the cost of shrubs $4.
Answer:
0.96
Step-by-step explanation:
price of 0.75 inch paper clip = 0.02$
To get price of 36 inches
0.75 --------0.02
36. --------. X
X = (36*0.02)/0.75 = 0.96$
I have no idea but good luck
Answer:
Step-by-step explanation:
1.
cot x sec⁴ x = cot x+2 tan x +tan³x
L.H.S = cot x sec⁴x
=cot x (sec²x)²
=cot x (1+tan²x)² [ ∵ sec²x=1+tan²x]
= cot x(1+ 2 tan²x +tan⁴x)
=cot x+ 2 cot x tan²x+cot x tan⁴x
=cot x +2 tan x + tan³x [ ∵cot x tan x 
=1]
=R.H.S
2.
(sin x)(tan x cos x - cot x cos x)=1-2 cos²x
L.H.S =(sin x)(tan x cos x - cot x cos x)
= sin x tan x cos x - sin x cot x cos x
= sin²x -cos²x
=1-cos²x-cos²x
=1-2 cos²x
=R.H.S
3.
1+ sec²x sin²x =sec²x
L.H.S =1+ sec²x sin²x
=
[
]
=1+tan²x ![[\frac{\textrm{sin x}}{\textrm{cos x}} = \textrm{tan x}]](https://tex.z-dn.net/?f=%5B%5Cfrac%7B%5Ctextrm%7Bsin%20x%7D%7D%7B%5Ctextrm%7Bcos%20x%7D%7D%20%3D%20%5Ctextrm%7Btan%20x%7D%5D)
=sec²x
=R.H.S
4.
L.H.S=
= 2 csc x
= R.H.S
5.
-tan²x + sec²x=1
L.H.S=-tan²x + sec²x
= sec²x-tan²x
=
=1
Answer:
54,000
Step-by-step explanation:
10^3=1000
1000*6=6000
6000*9=54000
