3 ten thousand + 14 tens + 16 ones

Mathematics

2 answers:

zzz [600]4 years ago

8 0

30,1416 I'm pretty sure this is the answer

swat324 years ago

3 0

"3 ten thousand" = 3 * 10,000
"14 tens" = 14 * 10
"16 ones" = 16 * 1

30,000 + 140 + 16 = 30,156

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Flura [38]

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3 years ago

Aunty Joan packs a packet of sweets to Alice and Olivia. Alice and Olivia share sweets in the ratio 7:3. Alice gives 3 sweets to

aivan3 [116]

Initially, Alice had 28 sweets and Olivia 12 sweets.

Step-by-step explanation:

First assume that Aunty Joan has x number sweets.

Alice and Olivia shared the x sweets in a ration of 7:3, this means

Alice had 7/10 x sweets and Olivia had 3/10 sweets.

Alice gives 3 sweets to Olivia, Alice will remain with ;

$\frac{7}{10} x-3$

Then the new ratio changes to 5:3 which means Alice will have 5/8 x number of sweets.

Equate the number of sweets for Alice in the two cases, which is

$\frac{5}{8}x=\frac{7}{10} x-3\\ \\\frac{7}{10} x-\frac{5}{8} x=3\\$

$\frac{56x-50x}{80} =3\\\\\\\frac{6}{80} x=3\\\\\\6x=80*3\\\\\\x=240/6\\\\x=40$

So there were 40 sweets at first

Using the ratio of 7:3 then

Alice had 7/10 *40 = 28 sweets

Olivia had 3/10*40= 12 sweets

Alice gave Olivia 3 sweets, so she will remain with 28-3 =25 sweets. Olivia will now have 15 sweets.The new ratio will be 25:15 simplified as 5:3.

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Ratio : brainly.com/question/11095585

Keywords : Ratio

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3 years ago

Let G denote the centroid of triangle ABC. If triangle ABG is equilateral with side length 2, then determine the perimeter of tr

zhannawk [14.2K]

We know from Euclidean Geometry and the properties of a centroid that GC=2GM. Now GM=sin60*GA= $\sqrt{3}$ . Hence CM=GC+GM=3* $\sqrt{3} /$ . Now, since GM is normal to AB, we have by the pythagoeran theorem that:
$AC^2=AM^2+GM^2=BM^2+GM^2=BC^2$
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