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madam [21]
3 years ago
9

Find the third side in simplest radical form

Mathematics
1 answer:
klasskru [66]3 years ago
3 0

Answer:

2 \sqrt{71}  \: units

Step-by-step explanation:

Given is a right angled triangle in which third side is the hypotenuse.

Therefore, by Pythagoras theorem:

thid \: side =  \sqrt{ {15}^{2}  + ( \sqrt{59} )^{2} }  \\  \\  =  \sqrt{225 + 59}  \\  \\  =  \sqrt{284}  \\  \\  =  \sqrt{ {2}^{2} \times 71 }  \\  \\  = 2 \sqrt{71}  \: units

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Help pls!! I’ll give Brainlist!! For questions 1-5 determine if the quadrilaterals are parallelograms or not. Beside the picture
tia_tia [17]

Answer:

1. no

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4. yes

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Step-by-step explanation:

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8 0
3 years ago
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Select the correct answer.
nydimaria [60]

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5 0
2 years ago
Are these lines parallel perpendicular or neither
Natasha_Volkova [10]

Answer:

perpendicular

Step-by-step explanation:

start but putting each line into the standard line format

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8 0
3 years ago
Devon and his friends bought strawberry wafers for $3 per packet and chocolate wafers for $1 per packet at a carnival. They spen
Irina-Kira [14]
Hi there!

PART A:
The system of equations we would use would be:
x + y = 22 (amount of items)
3x + 1y = 30 (cost)

Variables:
x = the amount of strawberry wafers bought at the price of $3
y = the amount of chocolate wafers bought at the price of $1

PART B:
To solve, we'll use substitution because we can easily isolate a variable using the first equation.

Work:
x + y = 22 (first equation)
y = 22 - x (isolating a variable)
3x + 1y = 30 (second equation)
3x + (22 - x) = 30 (substituting into the second equation)
2x + 22 = 30 (simplifying)
2x = 8 (subtracting)
x = 4 strawberry wafers
4 + y = 22 (substituting x into the first equation to solve for y)
y = 18 chocolate wafers

ANSWER:
They bought 4 strawberry wafers and 18 chocolate wafers.

Hope this helps!! :)
If there's anything else that I can help you with, please let me know!
8 0
4 years ago
What percent of 2000 is 204
Darina [25.2K]
204 is 10.2% of 2000

Working Out 

204/2000 x 100 = 10.2%
3 0
3 years ago
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