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2 years ago

Please simplify this

Mathematics

1 answer:

professor190 [17]2 years ago

8 0

Answer:

$\frac{3\sqrt{2} }{2}$

Step-by-step explanation:

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The product of 6x and ......

Amiraneli [1.4K]

the answer is true because 6x multiply -2 to give -12x and 6x multiplies x² to give 6x³

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1 year ago

The model below is used to represent the area of a square with a side length of /64 units.

Oxana [17]

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2 years ago

Read 2 more answers

What is the equation of this line? A: y=-3/2x B: y=2/3x C: y=-2/3x D: y=3/2x

creativ13 [48]

Answer:

b) y = 2/3x

Step-by-step explanation:

Slope (m) formula: $\frac{y_2-y_1}{x_2-x_1}$

I will be using (3,2) and (-3,-2) to find the slope:

$m=\frac{-2-2}{-3-3}\\m=\frac{-4}{-6} \\m = \frac{2}{3}$

$y = mx + b\\y = \frac{2}{3}x+b$

(3,2)

$y = \frac{2}{3}x+b\\\\2 = \frac{2}{3}(3)+b\\\\2 = 2+b\\-2 -2\\\\0=b$

$y=mx+b\\\\y = \frac{2}{3}x+0\\\\y = \frac{2}{3}x$

Hope this helps!

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1 year ago

A spinner is divided into four equal sections labeled A, B, C, D. After 50 trials, the spinner landed on A 14 times, on B 13 tim

svp [43]

Answer:

17/25

Step-by-step explanation:

P(not red)=Number of Skittles Not Red/Total Number of Skittles

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1 year ago

You know the measure of the exterior angle which forms a linear pair with the vertex angle. Describe two ways you can find measu

aev [14]

Answer:

Step-by-step explanation:

A linear pair are two given angles whose sum is equal to $180^{o}$ .

Let the exterior angle be represented by $x^{o}$ , and the three interior angles of the triangle be represented by $a^{o}$ , $b^{o}$ and $c^{o}$ .

Assume that the vertex angle $c^{o}$ is the linear pair to the exterior angle $x^{o}$ .

i.e $x^{o}$ + $c^{o}$ = $180^{o}$ (sum of angles on a straight line)

Thus,

i. $a^{o}$ + $b^{o}$ = $x^{o}$ (sum of two opposite interior angles is equal to an exterior angle)

⇒ $a^{o}$ = $x^{o}$ - $b^{o}$

Also,

$b^{o}$ = $x^{o}$ - $a^{o}$

But,

$a^{o}$ + $b^{o}$ + $c^{o}$ = $180^{o}$ (sum of angles in a triangle)

⇒ $c^{o}$ = $180^{o}$ - ( $a^{o}$ + $b^{o}$ )

and

$a^{o}$ + $b^{o}$ = $180^{o}$ - $c^{o}$

ii. $a^{o}$ + $b^{o}$ + $c^{o}$ = $180^{o}$ (sum of angles in a triangle)

$a^{o}$ = $180^{o}$ - ( $b^{o}$ + $c^{o}$ )

Also,

$a^{o}$ + $b^{o}$ = $x^{o}$

⇒ $b^{o}$ = $x^{o}$ - $a^{o}$

$c^{o}$ = $180^{o}$ - $x^{o}$

8 0

2 years ago