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Katarina [22]
2 years ago
14

HIII PLS HELP PLS SHOW ME ALL UR WORKINGS THXX​

Mathematics
2 answers:
vladimir1956 [14]2 years ago
8 0

Answer:

Step-by-step explanation:

(i) y = 3x

m = 3

Slope of the line perpendicular to line (y = 3x) = -1/m = -1/3

Equation of the line through origin : y = mx

y = \frac{-1}{3}x

(ii) Form of the equation of all lines which are perpendicular to y = 3x is

y = \frac{-1}{3}x +c

c is y-intercept

alexira [117]2 years ago
6 0
Y= -1/3 x is the answer

have a good day
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What is the standard form of (6x^2-8x-7)+(8x^2-76x)
Studentka2010 [4]

Answer:  14x^2 - 84x - 7

====================================================

Explanation:

The like terms 6x^2 and 8x^2 combine to 14x^2

The like terms -8x and -76x combine to -84x

Nothing pairs with the -7, so its stays as is.

Standard form is where we list the terms in decreasing exponent order. We can think of -84x as -84x^1 and the -7 as -7x^0. So 14x^2 - 84x - 7 would be the same as 14x^2 - 84x^1 - 7x^0. The exponents count down: 2,1,0.

The final answer is a trinomial since it has three terms. It is also a quadratic because the degree (highest exponent) is 2.

5 0
3 years ago
Bodmas 6x (3+8) -8x(6-2)​
Leona [35]
If your looking for the answer then it’s 34
4 0
3 years ago
Solve the equation: \frac{2}{3}t=\frac{5}{9} (hint: reciprocal)
Aleks04 [339]

Given:

\frac{2}{3}t=\frac{5}{9}\text{ We know that the reciprocal of }\frac{2}{3}\text{ is }\frac{3}{2}\text{.}

Multiply both sides by 3/2, we get

\frac{3}{2}\times\frac{2}{3}t=\frac{3}{2}\times\frac{5}{9}

Cancel out the common multiples, we get

t=\frac{1}{2}\times\frac{5}{3}

t=\frac{1\times5}{2\times3}

t=\frac{5}{6}

The solution of the given equation is

t=\frac{5}{6}

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t=0.8333.

3 0
1 year ago
Solve for y: 15 = y – 7
mixer [17]

Some number y has 7 subtracted off to get 15. We have y-7 = 15. To isolate y, we have to undo the "subtract 7" operation that happens to y. We have to add 7 to both sides.

y-7 = 15

y-7+7 = 15+7

y = 22 is the answer

8 0
3 years ago
Read 2 more answers
The lengths of the diagonals of a rhombus are 2x and 10x. What expression gives the perimeter of the rhombus?
True [87]

Answer:

P=4x\sqrt{26}\ units

Step-by-step explanation:

we know that

The sides of a rhombus are all congruent and the diagonals are perpendicular bisectors of each other

so

Applying the Pythagorean Theorem

c^2=a^2+b^2

where

c is the length side of the rhombus      

a and b are the semi-diagonals

we have

a=2x/2=x\ units\\b=10x/2=5x\ units

substitute the values

c^2=x^2+(5x)^2

c^2=26x^2

c=x\sqrt{26}\ units

To find out the perimeter of the rhombus multiply the length side by 4

P=(4)(x\sqrt{26})

P=4x\sqrt{26}\ units

6 0
3 years ago
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