Answer:
Set A's standard deviation is larger than Set B's
Step-by-step explanation:
Standard deviation is a measure of variation. One way to judge the value of standard deviation is by looking at the range of the data. In general, a dataset with a smaller range will have a smaller standard deviation.
The range of data Set A is 25-1 = 24.
The range of data Set B is 18-8 = 10.
Set A's range is larger, so we expect its standard deviation to be larger.
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The standard deviation is the root of the mean of the squares of the differences from the mean. In Set A, the differences are ±12, ±11, ±10. In Set B, the differences are ±5, ±3, ±1. We don't actually need to compute the RMS difference to see that it is larger for Set A.
Set A's standard deviation is larger than Set B's.
You do the following.
Take the price of the most expensive subscription and retract the price of the cheap one.
$50-$40 = $10
Since we know what the price of a text message and the difference in dollars between the two subscriptions, we can calculate how many text messages has to be sent. We just divide the result from before ($10) with the price of a text message ($0.2)
$10/$0.2 = 50
The total number of text messages that needs to be send in order for the price of the subscriptions to be the same, is 50.
Answer: the first option is the correct answer.
Step-by-step explanation:
Let x represent the number of necklaces that he makes in a year.
Profit = Revenue - cost
The cost of making each necklace is $5. In making necklaces in a year, the fixed cost is $5000. This means that the total cost of making x necklaces in a year is
5x + 5000
Sam sells each necklace for $10 each. This means that the total amount made from selling x necklaces is $10x.
For Sam to make profit of $1000 in a year, the number of necklaces that she must sell would be
1000 = 10x - (5x + 5000)
1000 = 10x - 5x - 5000
10x - 5x = 1000 + 5000
5x = 6000
x = 6000/5
x = 1200
The graph of g(x) = f(x) + 5 will have the graph of f(x) moved 5 units upward. The best choice is the last one.
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Adding 5 to each y-value (the output of f(x)) moves it upward by 5 units.
