Let ABC be a triangle in the 3rd quadrant, right-angled at B.
So, AB-> Perpendicular BC -> Base AC -> Hypotenuse.
Given: sinθ=-3/5 cosecθ=-5/3
According to Pythagorean theorem, square of the hypotenuse is equal to the sum of square of the other two sides.
Therefore in triangle ABC, 〖AC〗^2=〖AB〗^2+〖BC〗^2 ------
--(1)
Since sinθ=Perpendicular/Hypotenuse ,
AC=5 and AB=3
Substituting these values in equation (1)
〖BC〗^2=〖AC〗^2-〖AB〗^2
〖BC〗^2=5^2-3^2
〖BC〗^2=25-9
〖BC〗^2=16
BC=4 units
Since the triangle is in the 3rd quadrant, all trigonometric ratios, except tan
and cot are negative.
So,cosθ=Base/Hypotenuse Cosθ=-4/5
secθ=Hypotnuse/Base secθ=-5/4
tanθ=Perpendicular/Base tanθ=3/4
cotθ=Base/Perpendicular cotθ=4/3
B b b b b b b b b b b b b b b b b b b b b b b b b b b b b b.
Answer: 1 3/4 above sea level
the midpoint of 16 1/4 above sea level and 12 3/4 below sea level is 1 3/4 above sea level
Step-by-step explanation:
I made a line graph and brought each side closer and closer until i stopped at the middle point
Considering that point S splits segment RT, we have that:
a) The value of y is of y = 4.
b) The lengths are: RS = 29, ST = 19.
<h3>How to find the value of variable y?</h3>
Point S splits segment RT into two parts, hence the length of segment RT can be given by the following equation:
RT = RS + ST
The measures are given as follows:
Hence we can solve the equation for y, as follows:
RT = RS + ST
6y + 5 + 3y + 7 = 48.
9y = 36.
y = 4.
<h3>What are the lengths of segments RS and ST?</h3>
Considering that y = 4, we have that:
- RS = 6y + 5 = 6(4) + 5 = 29.
- ST = 3y + 7 = 3(4) + 7 = 19.
A similar problem, in which a point splits a segment, is given at brainly.com/question/4450896
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