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jekas [21]
2 years ago
5

jack got the expression 7x+1 and then wrote his answer as 1+7x is his answer an equivalment expression how do you know

Mathematics
1 answer:
Ugo [173]2 years ago
6 0
The equation was just flipped around, it will equal the same no matter what.

I hope this helps!! :)
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You have quarters and dimes that total $2.80. Your friend says it is possible that the number of quarters is 8 more than the num
AnnyKZ [126]

Answer:

Step-by-step explanation:

d = number of dimes

2.80 = 0.1d + 0.25 (d + 8 )

2.80 = 0.1d + 0.25d + 2            Combine like terms

2.80 = 0.35d + 2                       Subtract 2 from both sides

0.80 = 0.35d                             Divide both sides by 0.35

d ≈ 2.29

No, it's not possible to have more quarters than dimes when the total is $2.80 because it's not possible to have part of a dime.

5 0
3 years ago
11, 16, 12, 7, 23, 9, 5, 5 Question What is the median of the data?
valentina_108 [34]

Answer:

Step-by-step explanation:

add each number together

each of them should equal 88

then divide it by how many numbers there are. So it's 8.

this equals 11

3 0
3 years ago
Simplify<br><br> PLEASE HELP
SCORPION-xisa [38]

Answer: 3.83

Step-by-step explanation:

(2.24)(1.71)

=3.83

I think you just simply solve it

8 0
3 years ago
The expression -50 + 100 represents the balance, in dollars, of the banks account after x months.
Troyanec [42]

Answer:

maybe I think the answer is 50

3 0
3 years ago
The annual interest on a $15,000 $ ⁢ 15,000 investment exceeds the interest earned on an $8000 $ ⁢ 8000 investment by $685 $ ⁢ 6
Eduardwww [97]

Answer:

The interest rate on the $ 8, 000 investment is 9. 657 % = 9.66%

While the interest rate on the $ 15, 000 investment is 10.257% = 10.26%

Step-by-step explanation:

Generally, the formular for calculating simple interest, I is given by

I = (principal x rate x time) / 100

Let the the annual interest on the $8,000 investment be represented as I. While the rate is represented as R

Since the time is 1year, interest on the $8, 000 can be expressed as

I = ( 8000 x R × 1) ÷ 100

I = 8000R/100

I = 80R. ( eqn 1)

Also, let the annual interest on $15,000 investment be K and the rate be V

Since interest on $15, 000 is greater than that of the $8,000 by $685

K = I + 685

Also rate V is 0.6% higher than R

V = (R + 0.6)%

This the interest on the $15, 000 is expressed as

K = ( 15000 × V × 1) ÷ 100 (eqn 2)

Substitute for K and V in eqn 2

That is

I + 685 = ( 15000 x (R + 0.6) x 1) ÷ 100

I + 685 = 15000 (R + 0.6) ÷ 100

I + 685 = 150 (R + 0.6)

Open the bracket

I + 685 = 150R + 15 × 0.6

I + 685 = 150R + 9.

This is the same as

150R + 9 = I + 685. ( eqn 3)

Substitute eqn 1 into eqn 3

That is put

I = 80R in eqn 3

150R + 9 = 80R + 685

Collect like terms with R to one side

150R - 80 R = 685 - 9

70R = 676

R = 676 ÷ 70

R = 9.657 %

Recall that V = (R + 0.6)%

V = 10.257 %

Thus the interest rate on the $ 8, 000 investment is 9. 657 % = 9.66%

While the interest rate on the $ 15, 000 investment is 10.257% = 10.26%

8 0
3 years ago
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