We are given the graph of sine function.
First, we get the amplitude
A = [6 - (-2)] / 2
A = 4
Next, we determine the period and b
T = 4 - 0 = 4
b = 2π / T
b = π/2
The original sine function was
y = 4 sin πx/2
After the transformation, the equation now is
y = 4 sin [π(x+2)/2] + 2
<h2>
Hello!</h2>
The answer is: 
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Why?</h2>
Domain and range of trigonometric functions are already calculated, so let's discard one by one in order to find the correct answer.
The range is where the function can exist in the vertical axis when we assign values to the variable.
First:
: Incorrect, it does include 0.4 since the cosine range goes from -1 to 1 (-1 ≤ y ≤ 1)
Second:
: Incorrect, it also does include 0.4 since the cotangent range goes from is all the real numbers.
Third:
: Correct, the cosecant function is all the real numbers without the numbers included between -1 and 1 (y≤-1 or y≥1).
Fourth:
: Incorrect, the sine function range is equal to the cosine function range (-1 ≤ y ≤ 1).
I attached a pic of the csc function graphic where you can verify the answer!
Have a nice day!
Answer:
n = 8, w = 3 and perimeter = 122.83 units.
Step-by-step explanation:
Let the angle M is the angle between the equal sides of isosceles JAM.
So, JM = MA
⇒ 35 = 4n + 3
⇒ 4n = 32
⇒ n = 8 (Answer)
Now, if ∠ J = 14w - 1 and ∠ M = 98°, then
2(14w - 1) + 98 = 180
⇒ 2(14w - 1) = 82
⇒ 14w - 1 = 41
⇒ w = 3 (Answer)
Now, draw a perpendicular bisector on JA from vertex M and it meets JA at P say.
So, Δ MPJ will be a right triangle with ∠ J = (14w - 1) = 41° {Since w = 3}
Hence,
⇒ JP = 35 cos 41 = 26.415
So, JA = 2 × JP = 52.83
So, the perimeter of Δ JAM is = 35 × 2 + 52.83 = 122.83 units (Answer)
Correct answer is the last one.
Answer:
Yes she made an error. Explanation is below.
Step-by-step explanation:
Let the sample space for a six sided number cube be S

Let the event of a number getting greater than two be B

To find:
the probability of complement of B that is
p(~B) = ?
Solution"
First we need to solve probability for number getting greater than two

Now substituting the values we get


but we need complement of B so

P(complement of rolling a number greater than two) = 