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Pie
3 years ago
9

To make a pizza, I want to pick one type of crust, 1 type of sauce, and 1 type of topping. There are 3 crust types, 3 sauce type

s, and 9 toppings. How many different pizzas can I make?
Mathematics
1 answer:
Ede4ka [16]3 years ago
7 0

。☆✼★ ━━━━━━━━━━━━━━  ☾  

I believe you just multiply all the values together

3 x 3 x 9 = 81

You can make 81 different pizzas

Have A Nice Day ❤    

Stay Brainly! ヅ    

- Ally ✧    

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What proves m ∆ADB and ∆ADC are congruent.
AURORKA [14]

Answer: They're the same angles/measurements.

Step-by-step explanation: Look closely at both the angles. If you measure them, they will be the same because both angles look the same, but ΔADC's side is flipped.

Let me know if you have any questions.

~ Lily, from Brainly.

6 0
3 years ago
What’s the diameter of the circle of the circumference is 30 pi inches
ICE Princess25 [194]
30?
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30pi / 2pi = 15
15 = r
double the radius to get the diameter
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6 0
3 years ago
Read 2 more answers
Christmas candy and items are 80% off at Walgreens. Lacy got 3 rolls of wrapping paper originally priced at $4.99 each and a box
Maslowich

Answer:

A. $3.59

Step-by-step explanation:

Okay so wrapping paper 4.99 she got three. So we would take 4.99 and subtract 80%. We would get 0.998. We multiply this by three because that's how many she got. After multiplying it's 2.994, rounded just 2.99. She payed 2.99 for wrapping paper. Now with the candy canes, we take 2.99 and subtract 80%. 0.59. Added we get 3.58, and we can go ahead and round that up to $3.59. Before tax she payed $3.59.  

7 0
3 years ago
Bacteria triples every hour. How much bacteria will there be after two days if they started with 13,000 bacteria.
timofeeve [1]
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Hope this helps!
6 0
3 years ago
What is the quotient in simplified form? State any restrictions on the variable? \frac{x^2-16}{x^2+5x+6} /\frac{x^2+5x+4}{x^2-2x
lora16 [44]
\frac{x^2-16}{x^2+5x+6} / \frac{x^2+5x+4}{x^2-2x-8}

We can begin by rearranging this into multiplication:

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Now we can factor the numerators and denominators:

\frac{(x+4)(x-4)}{(x+3)(x+2)} * \frac{(x-4)(x+2)}{(x+4)(x+1)}

The factors (x+4) and (x+2) cancel out, leaving us with:

\frac{(x-4)}{(x+3)} * \frac{(x-4)}{(x+1)}

Our answer comes out to be:

\frac{(x-4)^{2} }{(x+3)(x+1)} or \frac{ x^{2} -8x+16}{ x^{2}+4x+3 }

Based on the numerator of the second fraction (since we used its inverse), the denominators of both, and the factors we canceled out earlier, the restrictions are x ≠ -4, -3, -2, -1, 4
4 0
3 years ago
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