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Pie
3 years ago
9

To make a pizza, I want to pick one type of crust, 1 type of sauce, and 1 type of topping. There are 3 crust types, 3 sauce type

s, and 9 toppings. How many different pizzas can I make?
Mathematics
1 answer:
Ede4ka [16]3 years ago
7 0

。☆✼★ ━━━━━━━━━━━━━━  ☾  

I believe you just multiply all the values together

3 x 3 x 9 = 81

You can make 81 different pizzas

Have A Nice Day ❤    

Stay Brainly! ヅ    

- Ally ✧    

。☆✼★ ━━━━━━━━━━━━━━  ☾

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Solve the equation -31=-6z-4z
jok3333 [9.3K]
<span>-31=-6z-4z
Subtract 4z from -6z
-31=-10z
Divide both sides by -10
Final Answer: 3.1 or 3 1/10</span>
8 0
3 years ago
What is the value of x in the equation 7x + 2y = 48 , when y = 3?
9966 [12]
<span>7x + 2y = 48
</span><span>7x + 2(3) = 48
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7x = 42
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answer </span><span>when y = 3,  x  = 6</span>
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3 years ago
The slope of a wheelchair ramp should
iren2701 [21]

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Step-by-step explanation:

4 0
3 years ago
The sum of two numbers is -17. Their difference is 41. Find the numbers.
Mnenie [13.5K]

Answer:

the two numbers are 12 and -29

Step-by-step explanation:

let the two numbers be x and y

let the sum of the two numbers b

x+y = -17 ..................................................... equation 1

let the difference between the two numbers be

x-y = 41 ........................................................................ equation 2

from equation 1

x+y = -17 ..................................................... equation 1

x = -17 - y ............................................................... equation 3

substitute for x in equation 2

x-y = 41 ........................................................................ equation 2

-17-y -y = 41

-17 -2y = 41

-2y = 41 + 17

-2y = 58

divide both sides by -2

-2y/-2 = 58/-2

y = -29

put the value of y = -29 in equation 3

x = -17 - y ............................................................... equation 3

x = -17-(-29)

x =-17 + 29

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5 0
3 years ago
The diagram shows the sector of a circle with the centre O and radius 6cm.
cricket20 [7]

Answer:

Area of the shaded region = 1.92 cm²

Step-by-step explanation:

From the picture attached,

Area of the shaded region = Area of the sector OMN - Area of the triangle OMN

Area of sector OMN = \frac{\theta}{360}(\pi r^{2})

Here, θ = Central angle of the sector

r = radius of the sector

Area of sector OMN = \frac{50}{360}(\pi )(6)^2

                                  = 15.708 square cm

Area of ΔOMN = 2(ΔOPN)

Area of ΔOPN = \frac{1}{2}(OP)(PN)

Area of ΔOMN = OP × PN

In ΔOPN,

sin(25°) = \frac{PN}{ON}

PN = ONsin(25°)

     = 6sin(25°)

     = 2.536 cm²

cos(25°) = \frac{OP}{ON}

OP = ONcos(25°)

OP = 6cos(25°)

OP = 5.438 cm

Area of ΔOMN = 2.536 × 5.438

                         = 13.791 cm²

Area of the shaded region = 15.708 - 13.791 = 1.917 cm²

                                             ≈ 1.92 cm²

3 0
3 years ago
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