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Viefleur [7K]
3 years ago
5

Is knowing the coordinates of the vertex of a parabola enough to determine the domain and range?

Mathematics
1 answer:
swat323 years ago
5 0

Answer:

no

Step-by-step explanation:

You need to know if it's open up or down

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What is the area of the trapezoid?<br><br> B1=12<br> B2=6<br> H=4
Oliga [24]
The formula for the area of a trapezoid is 1/2 (b1 + b2) h
So, take your b1 and b2, 12 and 6, and add them together. You get 18.
Divide this by 2, and you get 9.
Now, multiply 9 by your height, which is 4.
9 x 4 = 36.
The area of the trapezoid is 36 square inches.
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3 years ago
Solve x1/6+3/4=1/4 i have to add 20 characters
dangina [55]
X=-3
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8 0
3 years ago
Can someone help and explain this because I don't get it!
creativ13 [48]
The area of a triangle in determined by the formula:
\frac{b \times h}{2}
where b is the base of the triangle and h is it's height

You just have to replace the b and h with their values in the formula (b=9.9ft and h=5.5ft)
\frac{b \times h}{2}  =  \frac{9.9 \times 5.5}{2}  =27.225

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3 0
4 years ago
After obtaining a warrant, the police attached GPS tracking device to the car of a murder suspect. Suppose the car was located a
AURORKA [14]

Answer:

Part a) The coordinates of the suspect's car at its final destination are (4,4)

Part b) The distance traveled by the suspect was 10 miles

Part c) d=5.66\ mi

Step-by-step explanation:

The correct question in the attached figure

Part a) What are the coordinates of the suspect's car at its final destination?

we know that

The original position is the origin of a Cartesian coordinate system (0,0)

1) The suspect's car was tracked going 5 mi due east

That means----> 5 mi at right

the new coordinates are (5,0)

2) The suspect's car was tracked going 4 mi due north

That means----> 4 mi up

the new coordinates are (5,4)

3) The suspect's car was tracked going 1 mi due west

That means----> 1 mi at left

the new coordinates are (4,4)

therefore

The coordinates of the suspect's car at its final destination are (4,4)

Part b) What was the distance traveled by the suspect?

The distance traveled is  

5 mi due east + 4 mi due north + 1 mi due west

5+4+1=10\ mi

therefore

The distance traveled by the suspect was 10 miles

Part c)  What is the distance as the crow flies between the original position and the final position of the suspect's car?

the formula to calculate the distance between two points is equal to

d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}

Remember that

The original position was (0,0) and the final position was (4,4)

substitute in the formula

d=\sqrt{(4-0)^{2}+(4-0)^{2}}

d=\sqrt{(4)^{2}+(4)^{2}}

d=\sqrt{32}\ mi

d=5.66\ mi

5 0
3 years ago
Exercise 1<br><br> 4x...X4 =<br><br> 7 times
ikadub [295]
It’s 4 power 7 understand though the demonstration down :)
7
4
7 0
3 years ago
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