2 years ago

What is the factorization of 121b^4-49

Mathematics

1 answer:

Nezavi [6.7K]2 years ago

4 0

121^4-49

(11^2+7)(11^2-7) 1. 121. 49

11. × 11. 7 × 7

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Factor completely h^3+2h^2-9h-18

guapka [62]

Step 1: Group this into two groups:

$h^3 + 2h^2-9h-18=(h^3 + 2h^2)+(-9h-18)$

When you do that, be sure to group the "–" into the group with the 9 and make sure there's "+" between the groups.

Step 2: Factor out the GCF from both individual groups:

$(h^3 + 2h^2)+(-9h-18) = h^2 (h+2) -9(h+2)$

Step 3: Notice both groups have that (h+2)? That's a new GCF between the two groups, so factor that out:

$h^2 (h+2) -9(h+2) = (h+2)(h^2-9)$

Step 4: That $(h^2-9)$ piece can be factored further, since it's a difference of squares:

$(h+2)(h^2-9) = (h+2)(h+3)(h-3)$

Now it's factored.

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1 year ago

<img src="https://tex.z-dn.net/?f=p%5E%7B2%7Dxp%5E%7B2%7D" id="TexFormula1" title="p^{2}xp^{2}" alt="p^{2}xp^{2}" align="absmidd

vichka [17]

Answer:

${p}^{4} x$

Step-by-step explanation:

1) Regroup terms.

${p}^{2} p^{2} x$

2) Use product rule.

${p}^{2 + 2} x$

3) Simplify 2 × 2 to 4.

$p ^{4} x$

Therefor, the answer is p⁴x

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2 years ago

Read 2 more answers

1. A system of linear equations that has one solution has slopes that are__________

algol13

Answer:

different

Step-by-step explanation:

different slopes gives one solution

same slopes with different constant has no solution

same slopes and constants has many solutions

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