The length of B'C' in the rectangle A'B'C'D' = 9 units.
<u>Step-by-step explanation</u>:
step 1 :
Draw a rectangle with vertices ABCD in clockwise direction.
where, AB and DC are width of the rectangle ABCD.
AD and BC are length of the rectangle ABCD.
step 2 :
Now,
The length of the rectangle is AD = 5 units and
The width of the rectangle is AB = 3 units.
step 3 :
Draw another rectangle with vertices A'B'C'D' extended from vertices of the previous rectangle ABCD.
step 3 :
The length of the new rectangle is A'D' which is 4 units down from AD.
∴ The length of A'D' = length of AD + 4 units = 5+4 = 9 units
step 4 :
Since B'C' is also the length of the rectangle A'B'C'D', then the measure of B'C' is 9 units.
![\sqrt{9} +\sqrt{4}=5\\ \\\sqrt[3]{64}+\sqrt[3]{125}=9](https://tex.z-dn.net/?f=%5Csqrt%7B9%7D%20%2B%5Csqrt%7B4%7D%3D5%5C%5C%20%5C%5C%5Csqrt%5B3%5D%7B64%7D%2B%5Csqrt%5B3%5D%7B125%7D%3D9)
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Answer: 1
Step-by-step explanation:
Substitute
So, -2x-7 = 3x + 3
+2x. +2x
-7= 5x +3
-5x. -5x
-5x-7= 3
+7. +7
-5x= 10
Divide -5 on both sides and you get x= -2
Then substitute -2 in the first equation
-2(-2)-7
4-7
Y= -3
Answer: y = -6x + 8
Step-by-step explanation:
11 - y = 3 + 6x
<u>-11 -11</u>
<u>-y = -8 + 6x</u>
-1
y = -6x + 8
