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LiRa [457]
2 years ago
6

9. Your friend claims that you can prove that two parallelograms are congruent

Mathematics
1 answer:
laila [671]2 years ago
5 0
The answer is 45 okay bro good
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Select the point that is a solution to the system of inequalities​
ExtremeBDS [4]
<h3>Answer: B.  (-1, 0)</h3>

This point is below both the red diagonal line and the blue parabola. We know that the set of solution points is below both due to the "less than" parts of each inequality sign.  

In contrast, a point like (2,2) is above the parabola which is why it is not a solution. It does not make the inequality y \le x^2-3x true. So this is why we can rule choice A out.

Choice C is not a solution because (4,1) does not make y \le -x+3 true. This point is not below the red diagonal line. We can cross choice C off the list.

Choice D is similar to choice A, which is why we can rule it out as well.

5 0
3 years ago
16x+14y=8 <br> -63x-14y=133
artcher [175]

Answer:

(-3, 4)

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

<u>Algebra I</u>

  • Solving systems of equations using substitution/elimination
  • Solving systems of equations by graphing

Step-by-step explanation:

<u>Step 1: Define Systems</u>

16x + 14y = 8

-63x - 14y = 133

<u>Step 2: Solve for </u><em><u>x</u></em>

<em>Elimination</em>

  1. Combine 2 equations:                    -47x = 141
  2. Divide -47 on both sides:               x = -3

<u>Step 3: Solve for </u><em><u>y</u></em>

  1. Define original equation:                    16x + 14y = 8
  2. Substitute in <em>x</em>:                                     16(-3) + 14y = 8
  3. Evaluate multiplication:                       -48 + 14y = 8
  4. Add 48 on both sides:                        14y = 56
  5. Divide 14 on both sides:                      y = 4

<u>Step 4: Graph Systems</u>

<em>Check the solution set.</em>

4 0
2 years ago
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