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LiRa [457]
2 years ago
6

9. Your friend claims that you can prove that two parallelograms are congruent

Mathematics
1 answer:
laila [671]2 years ago
5 0
The answer is 45 okay bro good
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Use place value to find the product.
Aleonysh [2.5K]
3x600= 3 x 6 hundreds
= 18 hundreds
<span>= 1,800</span>
7 0
3 years ago
Ash invests £200 and gets 3% interest per year.<br> How much will she have after 5 years?
Taya2010 [7]

Answer:

£231.85

Step-by-step explanation:

→ Work out the decimal multiplier

( 3 + 100 ) ÷ 100 = 1.03

→ Multiply the initial investment by the multiplier raised to the power of years

200 × ( 1.03 )⁵ = £231.85

6 0
3 years ago
How do you solve -5m+9n= 15, for m
pentagon [3]
Well u add your problem and get your answer
4 0
3 years ago
Identify the lines that are perpendicular: A. = −5 and = 2 are perpendicularB. + 5 = 2 and − 5 + = 3 are perpendicularC. = 13 +
scZoUnD [109]

In order to check if the lines are perpendicular, we need to check if their slopes have the following relation (to find the slope we can use the slope-intercept form y = mx + b):

m_1=-\frac{1}{m_2}

A.

In this option, y = -5 is an horizontal line and x = 2 is a vertical line, therefore they are perpendicular.

B.

First let's find the slope of each line:

\begin{gathered} x+\frac{y}{5}=2 \\ 5x+y=10 \\ y=-5x+10\to m=-5 \\  \\ -\frac{x}{5}+y=3 \\ y=\frac{x}{5}+3\to m=\frac{1}{5} \end{gathered}

These slopes obey the relation stated above, so the lines are perpendicular.

C.

\begin{gathered} y=\frac{1}{3}x+1\to m=\frac{1}{3} \\  \\ y-1=-3(x-5) \\ y-1=-3x+15 \\ y=-3x+16\to m=-3 \end{gathered}

These slopes obey the relation stated above, so the lines are perpendicular.

D.

\begin{gathered} y-5=x+1 \\ y=x+6\to m=1 \\  \\ x+y=3 \\ y=-x+3\to m=-1 \end{gathered}

These slopes obey the relation stated above, so the lines are perpendicular.

E.

\begin{gathered} y+2=\frac{1}{3}(x-6) \\ y+2=\frac{1}{3}x-2 \\ y=\frac{1}{3}x-4\to m=\frac{1}{3} \\  \\ y=3x+4\to m=3 \end{gathered}

These slopes don't obey the relation stated above, so the lines aren't perpendicular.

The correct options are A, B, C and D.

5 0
1 year ago
(03.06) Given the equation y − 3 = one half (x + 6) in point-slope form, identify the equation of the same line in slope interce
Anvisha [2.4K]
Y-3=(1/2)(x+6). just solve for y
y-3=1/2x +3
y = 1/2x + 6

5 0
3 years ago
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