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Naily [24]
3 years ago
6

Is (1,3) a solution of the graphed inequality?

Mathematics
1 answer:
BaLLatris [955]3 years ago
5 0

Answer:

yes.

Step-by-step explanation:

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HELP CALCULUS 25 POINTS
shepuryov [24]

Answer:

A.) Max at x = 6 and Min at x = -6

Step-by-step explanation:

We say that f(x) has a relative (or local) maximum at x=c if f(x)≤f(c) f ( x ) ≤ f ( c ) for every x in some open interval around x=c . We say that f(x) has an absolute (or global) minimum at x=c if f(x)≥f(c) f ( x ) ≥ f ( c ) for every x in the domain we are working on.

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3 years ago
If fx= 6x-4 what is<br> when x=8
ra1l [238]

Answer:

44

Step-by-step explanation:

fx=6(8)-4

fx=48-4

fx=44

6 0
3 years ago
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Write fractions in simplest form. -9/2 + 5/12
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If you multiply 12 by
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3 years ago
Find the value of x<br> .
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Work out in a standard form. <br>A) 2.1x 10^-5 ÷7 x 10^-2​
EleoNora [17]

\huge\underline{\underline{\boxed{\mathbb {SOLUTION:}}}}

<h3>Given:</h3>

▪ \longrightarrow \sf{\dfrac{2.1 \times  {10}^{5} }{7 \times  {10}^{ - 2} } }

First, rewrite the numerator in such a way that the coefficient 2.1 becomes 21:

\small\longrightarrow \sf{\dfrac{21 \times  {10}^{ - 6} }{7 \times  {10}^{2} } }

Divide the coefficient:

\small\longrightarrow \sf{21 \div 7=3}

Divide the base by subtracting the exponents of the base 10.

\small\longrightarrow \sf{-6(-2) \Longrightarrow -6+2=-4}

\leadsto Hence, the quotient of the given expression has a coefficient of 3 and the exponent of the base 10 is -4.

\small\longrightarrow \sf{3 \times 10^{-4}}

\huge\underline{\underline{\boxed{\mathbb {ANSWER:}}}}

\large \bm{The \:  \: quotient \:  \: is  \: \: 3 \times  {10}^{ - 4} .}

5 0
10 months ago
Read 2 more answers
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