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3 years ago

Is (1,3) a solution of the graphed inequality?

Mathematics

1 answer:

BaLLatris [955]3 years ago

5 0

Answer:

yes.

Step-by-step explanation:

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3 years ago

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harkovskaia [24]

Answer:

a¹⁸b²⁴c⁵⁴

Step-by-step explanation:

(aᵇ)ᶜ = aᵇᶜ = aᵇ×ᶜ

(-aⁿ)ᵒᵈᵈ = -aⁿ

(-aⁿ)ᵉᵛᵉⁿ = aⁿ

aⁿ × aⁿ = aⁿ⁺ⁿ

_________

In this situation, 6 is an even exponent which means that the negative coefficient of this 9th degree monomial will be positive. Now the only step is to multiply the exponents by the exponent outside of the perenthesis which is 6.

so (-a³b⁴c⁹)⁶ = ((-a³)⁶(b⁴)⁶(c⁹)⁶) = ((a³ˣ⁶)(b⁴ˣ⁶)(c⁹ˣ⁶)) = ((a¹⁸)(b²⁴)(c⁵⁴)) = <em>a¹⁸b²⁴c⁵⁴</em>

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3 years ago

What is an equation of the line that passes through the points (-6, -2) and

den301095 [7]

Answer:

The equation of line is: $\mathbf{4x-3y=-18}$

Step-by-step explanation:

We need to find an equation of the line that passes through the points (-6, -2) and (-3, 2)?

The equation of line in slope-intercept form is: $y=mx+b$

where m is slope and b is y-intercept.

We need to find slope and y-intercept.

Finding Slope

Slope can be found using formula: $Slope=\frac{y_2-y_1}{x_2-x_1}$

We have $x_1=-6,y_1=-2, x_2=-3, y_2=2$

Putting values and finding slope

$Slope=\frac{2-(-2)}{-3-(-6)}\\Slope=\frac{2+2}{-3+6} \\Slope=\frac{4}{3}$

So, we get slope: $m=\frac{4}{3}$

Finding y-intercept

Using point (-6,-2) and slope $m=\frac{4}{3}$ we can find y-intercept

$y=mx+b\\-2=\frac{4}{3}(-6)+b\\-2=4(-2)+b\\-2=-8+b\\b=-2+8\\b=6$

So, we get y-intercept b= 6

Equation of required line

The equation of required line having slope $m=\frac{4}{3}$ and y-intercept b = 6 is

$y=mx+b\\y=\frac{4}{3}x+6$

Now transforming in fully reduced form:

$y=\frac{4x+6*3}{3} \\y=\frac{4x+18}{3} \\3y=4x+18\\4x-3y=-18$

So, the equation of line is: $\mathbf{4x-3y=-18}$

6 0

2 years ago